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Exact Solutions and Scalar Fields in Gravity - Instituto Avanzado de ...

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The superposition of null dustbeams <strong>in</strong> General Relativity 59<br />

For match<strong>in</strong>g it is convenient to use the physical distance L from the<br />

symmetry axis as the radial coord<strong>in</strong>ate <strong>in</strong> the <strong>in</strong>terior <strong>and</strong> exterior metrics<br />

<strong>in</strong>stead of the coord<strong>in</strong>ates <strong>and</strong> which are related to L by the<br />

relations<br />

The boundary conditions at the surface imply the relation<br />

between the real parameters <strong>in</strong> the <strong>in</strong>terior, <strong>in</strong> the exterior, <strong>and</strong> the<br />

radius of the boundary surface.<br />

3.3. THE STATIONARY SOLUTION<br />

Now we will treat the stationary case when the Kill<strong>in</strong>g vectors<br />

(timelike) <strong>and</strong> (spacelike) are not hypersurface–orthogonal. In this<br />

case we can start with the non–diagonal l<strong>in</strong>e element<br />

The <strong>de</strong>rivation of the stationary solution is very similar to the procedure<br />

applied <strong>in</strong> the static case. The result<strong>in</strong>g stationary metric<br />

can be obta<strong>in</strong>ed from its static counterpart (18) with the aid of the<br />

complex substitution<br />

The <strong>in</strong>terior solution (27) can be matched to an exterior vacuum solution<br />

which is also related to (24) by a complex substitution.<br />

The two solutions (18) <strong>and</strong> (27) <strong>de</strong>scribe physically different situations.<br />

In both cases the photons which form the source of the gravitational<br />

field move along screwed l<strong>in</strong>es on the cyl<strong>in</strong><strong>de</strong>r mantle (<br />

<strong>and</strong> have no ) <strong>and</strong> surround the axis However,<br />

<strong>in</strong> the static case the photons of the beam with propagation vector<br />

<strong>and</strong> those with move on the same trajectories <strong>in</strong> opposite directions<br />

whereas <strong>in</strong> the stationary case they move on different screwed curves<br />

with the same sense of revolution. Thus the total rotation of the source<br />

is zero because of compensation <strong>in</strong> the static solution (18) <strong>and</strong> it does

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