Dissertation - Michael Becker

(51)IDENT IDENT σ1saÙ IDENT σ1taÙ *VÙVa. saÙ-ı ≻ saÃ-ı W W Lb. taÃ-ı ≻ taÙ-ı L L Wc. anaÙ-ı ≻ anaÃ-ı W Ld. amaÃ-ı ≻ amaÙ-ı L WThe column of IDENT(voice) σ1saÙ has no L’s in it, so it can be installed, and the firstwinner-loser pair can be removed from the tableau. While the mono-syllabic Ù -final nounswere successfully listed by clones of IDENT(voice) σ1 , the learner is not quite ready todiscover the rest of the Ù -final nouns. Given the tableau in (51), there are no constraintsto install after the installation of IDENT(voice) σ1saÙ , so either IDENT(voice) or *VÙV willneed to cloned. Once either of them is cloned, taÙ and amach will be listed with one clone,and anaÙ will be listed with the other. Assuming it is IDENT(voice) that is cloned, theresulting grammar will be the one in (52).(52) IDENT(voice) σ1saÙ ≫ IDENT(voice) anaÙ ≫ *VÙV ≫IDENT(voice) σ1taÙ , IDENT(voice) taÙ, amaÙThe problem with the grammar in (52) is that the lexicon is not neatly partitioned inthe way the learner needs it to be: The specific IDENT(voice) σ1 correctly lists all and onlythe mono-syllables, but the general IDENT(voice), in addition to correctly listing all thepoly-syllabic Ù -final nouns, also incorrectly lists the mono-syllabic Ù -final alternators.The problem is that the general IDENT(voice) assigns W’s and L’s to all nouns,regardless of size, potentially allowing some nouns to “double dip”, as seen in (52).To ensure that nouns are not listed multiple times, the learner needs to make sure that54