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PERCOLATION AND DISORDERED SYSTEMS Geoffrey GRIMMETT

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268 <strong>Geoffrey</strong> Grimmett<br />

Evidently pg(q) ≤ pc(q), and it is believed that equality is valid here. Next,<br />

we define the kth iterate of (natural) logarithm by<br />

λ1(n) = log n, λk(n) = log + {λk−1(n)} for k ≥ 2<br />

where log + x = max{1, logx}.<br />

We present the next theorem in two parts, and shall give a full proof of<br />

part (a) only; for part (b), see [167].<br />

Theorem 13.17. Let 0 < p < 1 and q ≥ 1, and assume that p < pg(q).<br />

(a) If k ≥ 1, there exists α = α(p, q, k) satisfying α > 0 such that<br />

(13.18) φ 0 � � �<br />

p,q 0 ↔ ∂B(n) ≤ exp −αn/λk(n) � for all large n.<br />

(b) If (13.18) holds, then there exists β = β(p, q) satisfying β > 0 such<br />

that<br />

φ 0 � � −βn<br />

p,q 0 ↔ ∂B(n) ≤ e for all large n.<br />

The spirit of the theorem is close to that of Hammersley [175] and Simon–<br />

Lieb [236, 331], who derived exponential estimates when q = 1, 2, subject to<br />

a hypothesis of finite susceptibility (i.e., that �<br />

x φ0p,q(0 ↔ x) < ∞). The<br />

latter hypothesis is slightly stronger than the assumption of Theorem 13.17<br />

when d = 2.<br />

Underlying any theorem of this type is an inequality. In this case we use<br />

two, of which the first is a consequence of the following version of Russo’s<br />

formula, taken from [74].<br />

Theorem 13.19. Let 0 < p < 1, q > 0, and let ψp be the corresponding<br />

random-cluster measure on a finite graph G = (V, E). Then<br />

d<br />

dp ψp(A)<br />

1 �<br />

= ψp(N1A) − ψp(N)ψp(A)<br />

p(1 − p)<br />

�<br />

for any event A, where N = N(ω) is the number of open edges of a configuration<br />

ω.<br />

Here, ψp is used both as probability measure and expectation operator.<br />

Proof. We express ψp(A) as<br />

ψp(A) =<br />

�<br />

ω 1A(ω)πp(ω)<br />

�<br />

ω πp(ω)<br />

where πp(ω) = p N(ω) (1 −p) |E|−N(ω) q k(ω) . Now differentiate throughout with<br />

respect to p, and gather the terms to obtain the required formula. �

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