PERCOLATION AND DISORDERED SYSTEMS Geoffrey GRIMMETT
PERCOLATION AND DISORDERED SYSTEMS Geoffrey GRIMMETT
PERCOLATION AND DISORDERED SYSTEMS Geoffrey GRIMMETT
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184 <strong>Geoffrey</strong> Grimmett<br />
Similarly,<br />
Pp({ρk > rk} ∩ An ∩ B)<br />
= �<br />
Pp(B, G = Γ)Pp({ρk > rk} ∩ An | B, G = Γ)<br />
Γ<br />
= �<br />
Pp(B, G = Γ)<br />
Γ<br />
× Pp<br />
� �y(Γ) ↔ ∂S(rk + 1, y(Γ)) off Γ � ◦ � y(Γ) ↔ ∂S(n) off Γ ��<br />
.<br />
We apply the BK inequality to the last term to obtain<br />
(3.16)<br />
Pp({ρk > rk} ∩ An ∩ B)<br />
≤ �<br />
� �<br />
Pp(B, G = Γ)Pp y(Γ) ↔ ∂S(n) off Γ<br />
Γ<br />
× Pp<br />
≤ gp(rk + 1)Pp(An ∩ B)<br />
by (3.15) and the fact that, for each possible Γ,<br />
Pp<br />
�<br />
y(Γ) ↔ ∂S � rk + 1, y(Γ) � �<br />
off Γ<br />
�<br />
y(Γ) ↔ ∂S � rk + 1, y(Γ) � �<br />
off Γ<br />
≤ Pp<br />
�<br />
y(Γ) ↔ ∂S � rk + 1, y(Γ) ��<br />
= Pp(Ark+1)<br />
= gp(rk + 1).<br />
We divide each side of (3.16) by Pp(An ∩ B) to obtain<br />
Pp(ρk ≤ rk | An ∩ B) ≥ 1 − gp(rk + 1),<br />
throughout which we multiply by Pp(B | An) to obtain the result. �<br />
(3.17) Lemma. For 0 < p < 1, it is the case that<br />
� �<br />
(3.18) Ep N(An) | An ≥<br />
Proof. It follows from Lemma (3.12) that<br />
� n<br />
i=0<br />
n<br />
− 1.<br />
gp(i)<br />
(3.19) Pp(ρ1 +ρ2+· · ·+ρk ≤ n−k | An) ≥ P(M1+M2+· · ·+Mk ≤ n−k),<br />
where k ≥ 1 and M1, M2, . . . is a sequence of independent random variables<br />
distributed as M. We defer until the end of this proof the minor chore of