PERCOLATION AND DISORDERED SYSTEMS Geoffrey GRIMMETT
PERCOLATION AND DISORDERED SYSTEMS Geoffrey GRIMMETT
PERCOLATION AND DISORDERED SYSTEMS Geoffrey GRIMMETT
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186 <strong>Geoffrey</strong> Grimmett<br />
It remains to show that (3.19) follows from Lemma (3.12). We have that<br />
Pp(ρ1 + ρ2 + · · · + ρk ≤ n − k | An)<br />
n−k �<br />
= Pp(ρ1 + ρ2 + · · · + ρk−1 = i, ρk ≤ n − k − i | An)<br />
i=0<br />
n−k �<br />
≥ P(M ≤ n − k − i)Pp(ρ1 + ρ2 + · · · + ρk−1 = i | An) by (3.13)<br />
i=0<br />
= Pp(ρ1 + ρ2 + · · · + ρk−1 + Mk ≤ n − k | An),<br />
where Mk is a random variable which is independent of all edge-states in<br />
S(n) and is distributed as M. There is a mild abuse of notation here, since<br />
Pp is not the correct probability measure unless Mk is measurable on the<br />
usual σ-field of events, but we need not trouble ourselves overmuch about<br />
this. We iterate the above argument in the obvious way to deduce (3.19),<br />
thereby completing the proof of the lemma. �<br />
The conclusion of Theorem (3.8) is easily obtained from this lemma, but<br />
we delay this step until the end of the section. The proof of Theorem (3.4)<br />
proceeds by substituting (3.18) into (3.11) to obtain that, for 0 ≤ α < β ≤ 1,<br />
gα(n) ≤ gβ(n)exp<br />
�<br />
−<br />
� β<br />
α<br />
�<br />
� n<br />
i=0<br />
� �<br />
n<br />
− 1 dp .<br />
gp(i)<br />
It is difficult to calculate the integral in the exponent, and so we use the<br />
inequality gp(i) ≤ gβ(i) for p ≤ β to obtain<br />
(3.22) gα(n) ≤ gβ(n)exp<br />
�<br />
−(β − α)<br />
�<br />
� n<br />
i=0<br />
��<br />
n<br />
− 1 ,<br />
gβ(i)<br />
and it is from this relation that the conclusion of Theorem (3.4) will be<br />
extracted. Before continuing, it is interesting to observe that by combining<br />
(3.10) and (3.18) we obtain a differential-difference inequality involving the<br />
function<br />
n�<br />
G(p, n) = gp(i);<br />
rewriting this equation rather informally as a partial differential inequality,<br />
we obtain<br />
(3.23)<br />
i=0<br />
∂2G ∂G<br />
�<br />
n<br />
�<br />
≥ − 1 .<br />
∂p ∂n ∂n G<br />
Efforts to integrate this inequality directly have failed so far.