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PERCOLATION AND DISORDERED SYSTEMS Geoffrey GRIMMETT

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186 <strong>Geoffrey</strong> Grimmett<br />

It remains to show that (3.19) follows from Lemma (3.12). We have that<br />

Pp(ρ1 + ρ2 + · · · + ρk ≤ n − k | An)<br />

n−k �<br />

= Pp(ρ1 + ρ2 + · · · + ρk−1 = i, ρk ≤ n − k − i | An)<br />

i=0<br />

n−k �<br />

≥ P(M ≤ n − k − i)Pp(ρ1 + ρ2 + · · · + ρk−1 = i | An) by (3.13)<br />

i=0<br />

= Pp(ρ1 + ρ2 + · · · + ρk−1 + Mk ≤ n − k | An),<br />

where Mk is a random variable which is independent of all edge-states in<br />

S(n) and is distributed as M. There is a mild abuse of notation here, since<br />

Pp is not the correct probability measure unless Mk is measurable on the<br />

usual σ-field of events, but we need not trouble ourselves overmuch about<br />

this. We iterate the above argument in the obvious way to deduce (3.19),<br />

thereby completing the proof of the lemma. �<br />

The conclusion of Theorem (3.8) is easily obtained from this lemma, but<br />

we delay this step until the end of the section. The proof of Theorem (3.4)<br />

proceeds by substituting (3.18) into (3.11) to obtain that, for 0 ≤ α < β ≤ 1,<br />

gα(n) ≤ gβ(n)exp<br />

�<br />

−<br />

� β<br />

α<br />

�<br />

� n<br />

i=0<br />

� �<br />

n<br />

− 1 dp .<br />

gp(i)<br />

It is difficult to calculate the integral in the exponent, and so we use the<br />

inequality gp(i) ≤ gβ(i) for p ≤ β to obtain<br />

(3.22) gα(n) ≤ gβ(n)exp<br />

�<br />

−(β − α)<br />

�<br />

� n<br />

i=0<br />

��<br />

n<br />

− 1 ,<br />

gβ(i)<br />

and it is from this relation that the conclusion of Theorem (3.4) will be<br />

extracted. Before continuing, it is interesting to observe that by combining<br />

(3.10) and (3.18) we obtain a differential-difference inequality involving the<br />

function<br />

n�<br />

G(p, n) = gp(i);<br />

rewriting this equation rather informally as a partial differential inequality,<br />

we obtain<br />

(3.23)<br />

i=0<br />

∂2G ∂G<br />

�<br />

n<br />

�<br />

≥ − 1 .<br />

∂p ∂n ∂n G<br />

Efforts to integrate this inequality directly have failed so far.

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