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Complex Analysis - Maths KU

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122 Chapter 2 <strong>Complex</strong> Functions and Mappings<br />

In Definition 2.9 we defined continuityof a complex function f at a single<br />

point z0 in the complex plane. We are often also interested in the continuity<br />

of a function on a set of points in the complex plane. A complex function<br />

f is continuous on a set S if f is continuous at z0 for each z0 in S. For<br />

example, using Theorem 2.2 and the limits in (15) and (16), as in Example<br />

5, we can show that f(z) =z2 − iz + 2 is continuous at anypoint z0 in the<br />

complex plane. Therefore, we saythat f is continuous on C. The function<br />

f(z) =<br />

1<br />

z2 is continuous on the set consisting of all complex z such that<br />

+1<br />

z �= ±i.<br />

Properties of Continuous Functions Because the concept of<br />

continuityis defined using the complex limit, various properties of complex<br />

limits can be translated into statements about continuity. Consider Theorem<br />

2.1, which describes the connection between the complex limit of f(z) =<br />

u(x, y)+iv(x, y) and the real limits of u and v. Using the following definition<br />

of continuityfor real functions F (x, y), we can restate this theorem about<br />

limits as a theorem about continuity.<br />

Continuity of a Real Function F (x, y)<br />

A function F is continuous at a point (x0, y0) if<br />

lim<br />

(x,y)→(x0,y0) F (x, y) =F (x0, y0). (20)<br />

Again, this definition of continuityis analogous to (17). From (20) and Theorem<br />

2.1, we obtain the following result.<br />

Theorem 2.3 Real and Imaginary Parts of a Continuous Function<br />

Suppose that f(z) =u(x, y) +iv(x, y) and z0 = x0 + iy0. Then the<br />

complex function f is continuous at the point z0 if and onlyif both real<br />

functions u and v are continuous at the point (x0, y0).<br />

Proof Assume that the complex function f is continuous at z0. Then from<br />

Definition 2.9 we have:<br />

lim f(z) =f(z0) =u(x0, y0)+iv(x0, y0). (21)<br />

z→z0<br />

ByTheorem 2.1, this implies that:<br />

lim<br />

(x,y)→(x0,y0) u(x, y) =u(x0, y0) and lim<br />

(x,y)→(x0,y0) v(x, y) =v(x0, y0). (22)<br />

Therefore, from (20), both u and v are continuous at (x0, y0). Conversely, if<br />

u and v are continuous at (x0, y0), then<br />

lim<br />

(x,y)→(x0,y0) u(x, y) =u(x0,y0) and lim<br />

(x,y)→(x0,y0) v(x, y) =v(x0, y0).

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