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Complex Analysis - Maths KU

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y<br />

x 1<br />

(a) A ray emanating from x 1<br />

v<br />

φ<br />

α/ π<br />

w = (z – x1 )<br />

α φ/<br />

π<br />

(b) Image of the ray in (a)<br />

Figure 7.20 The mapping<br />

w =(z − x1) α/π<br />

y<br />

0<br />

x 1<br />

(a) The half-plane y ≥ 0<br />

v<br />

α/ π<br />

w = (z – x1 )<br />

α<br />

(b) The image of the half-plane<br />

Figure 7.21 The mapping<br />

w =(z − x1) α/π<br />

0<br />

x<br />

u<br />

x<br />

u<br />

7.3 Schwarz-Christoffel Transformations 411<br />

function F (z) =z α/π . Because x1 is real, T translates in a direction parallel<br />

to the real axis. Under this translation the x-axis is mapped onto the u-axis<br />

with the point z = x1 mapping onto the point w = 0. In order to understand<br />

the power function F as a complex mapping we replace the symbol z with the<br />

exponential notation re iθ to obtain:<br />

F (z) = � re iθ�α/π = r α/π e i(αθ/π) . (2)<br />

From (2) we see that the complex mapping w = z α/π can be visualized as the<br />

process of magnifying or contracting the modulus r of z to the modulus r α/π of<br />

w, and rotating z through α/π radians about the origin to increase or decrease<br />

an argument θ of z to an argument αθ/π of w. Thus, under the composition<br />

w = F (T (z)) = (z − x1) α/π , a rayemanating from x1 and making an angle of<br />

φ radians with the real axis is mapped onto a rayemanating from the origin<br />

and making an angle of αφ/π radians with the real axis. See Figure 7.20.<br />

Now consider the mapping (1) on the half-plane y ≥ 0. Since this set<br />

consists of the point z = x1 together with the set of rays arg(z − x1) =φ,<br />

0 ≤ φ ≤ π, the image under w =(z− x1) α/π consists of the point w =0<br />

together with the set of rays arg(w) =αφ/π, 0≤ αφ/π ≤ α. Put another<br />

way, the image of the half-plane y ≥ 0 is the point w = 0 together with the<br />

wedge 0 ≤ arg(w) ≤ α. See Figure 7.21.<br />

The function f given by(1), which maps the half-plane y ≥ 0ontoan<br />

unbounded polygonal region with a single vertex, has derivative:<br />

f ′ (z) = α<br />

π (z − x1) (α/π)−1 . (3)<br />

Since f ′ (z) �= 0ifz = x+iy and y>0, it follows that w = f(z) is a conformal<br />

mapping at anypoint z with y>0. In general, we will use the derivative<br />

f ′ , not f, to describe a conformal mapping of the upper half-plane y ≥ 0<br />

onto an arbitrarypolygonal region. With this in mind, we will now present a<br />

generalization of the mapping in (1) based on its derivative in (3).<br />

Consider a new function f, which is analytic in the domain y>0 and<br />

whose derivative is:<br />

f ′ (z) =A (z − x1) (α1/π)−1 (z − x2) (α2/π)−1 , (4)<br />

where x1, x2, α1, and α2 are real, x1

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