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Complex Analysis - Maths KU

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1.3 Polar Form of <strong>Complex</strong> Numbers 21<br />

(iv) The “cosine i sine” part of the polar form of a complex number is<br />

sometimes abbreviated cis.That is,<br />

z = r (cos θ + i sin θ) =r cis θ.<br />

This notation, used mainly in engineering, will not be used in this<br />

text.<br />

EXERCISES 1.3 Answers to selected odd-numbered problems begin on page ANS-2.<br />

In Problems 1–10, write the given complex number in polar form first using an<br />

argument θ �= Arg(z) and then using θ = Arg(z).<br />

1. 2 2. −10<br />

3. −3i 4. 6i<br />

5. 1+i 6. 5 − 5i<br />

7. − √ 3+i 8. −2 − 2 √ 3i<br />

9.<br />

3<br />

−1+i<br />

10.<br />

12<br />

√ 3+i<br />

In Problems 11 and 12, use a calculator to write the given complex number in polar<br />

form first using an argument θ �= Arg(z) and then using θ = Arg(z).<br />

11. − √ 2+ √ 7i 12. −12 − 5i<br />

In Problems 13 and 14, write the complex number whose polar coordinates (r, θ)<br />

are given in the form a + ib. Use a calculator if necessary.<br />

13. (4, −5π/3) 14. (2, 2)<br />

In Problems 15–18, write the complex number whose polar form is given in the form<br />

a + ib. Use �a<br />

calculator if necessary.<br />

15. z =5 cos 7π<br />

�<br />

7π<br />

+ i sin 16. z =8<br />

6 6<br />

√ �<br />

2 cos 11π<br />

�<br />

11π<br />

+ i sin<br />

4 4<br />

�<br />

17. z =6 cos π π<br />

�<br />

�<br />

+ i sin 18. z =10 cos<br />

8 8<br />

π π<br />

�<br />

+ i sin<br />

5 5<br />

In Problems 19 and 20, use (6) and (7) to find z1z2 and z1/z2. Write the number<br />

in the form a + ib.<br />

�<br />

19. z1 =2 cos π π<br />

� �<br />

+ i sin , z2 =4 cos<br />

8 8<br />

3π<br />

�<br />

3π<br />

+ i sin<br />

8 8<br />

20. z1 = √ �<br />

2 cos π π<br />

�<br />

+ i sin , z2 =<br />

4 4<br />

√ �<br />

3 cos π π<br />

�<br />

+ i sin<br />

12 12<br />

In Problems 21–24, write each complex number in polar form. Then use either (6)<br />

or (7) to obtain the polar form of the given number. Finally, write the polar form<br />

in the form a + ib.<br />

21. (3 − 3i)(5+5 √ 3i) 22. (4 + 4i)(−1+i)<br />

23. −i<br />

1+i<br />

24.<br />

√ √<br />

2+ 6i<br />

−1+ √ 3i

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