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Complex Analysis - Maths KU

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430 Chapter 7 Conformal Mappings<br />

y<br />

∇ = 0<br />

2<br />

Φ<br />

v<br />

∇ φ = 0<br />

2<br />

φ = 30 φ = 0<br />

1<br />

(a) Dirichlet problem<br />

Φ=<br />

0<br />

r 0<br />

2 3<br />

Φ = 30<br />

(b) Transformed Dirichlet problem<br />

Figure 7.48 Figure for Example 1<br />

1<br />

x<br />

u<br />

In the following examples, we will applysome ideas from the preceding<br />

sections in this chapter to help solve Dirichlet problems arising in the areas<br />

of electrostatics, fluid flow, and heat flow. Recall from Section 3.3 that if<br />

a function φ(x, y) satisfies Laplace’s equation (1) in some domain D, then<br />

φ(x, y) is harmonic in D. Moreover, if ψ(x, y) is a harmonic conjugate of<br />

φ(x, y) inD, then the function<br />

Ω(z) =φ(x, y)+iψ(x, y)<br />

is analytic in D and is called a complex potential function. The level<br />

curves of φ and ψ have important physical interpretations in applied mathematics.<br />

Their interpretations are summarized in Table 3.1 of Section 3.4.<br />

EXAMPLE 1 A Heat Flow Application<br />

Determine the steady-state temperature φ in the domain D consisting of all<br />

points outside of the two circles |z| = 1 and � �<br />

� 5 z − � 1<br />

2 = 2 , shown in color in<br />

Figure 7.48(a), that satisfies the indicated boundaryconditions.<br />

Solution The steady-state temperature φ is a solution of Laplace’s equation<br />

(1) in D that satisfies the boundaryconditions<br />

φ(x, y) = 30 if x 2 + y 2 =1,<br />

φ(x, y) =0 if � x − 5<br />

�2 2 1<br />

2 + y = 4 .<br />

We solve this problem using the four steps given on page 429.<br />

Step 1 EntryC-1 in Appendix III indicates that we can map D onto an<br />

annulus. Identifying b = 2 and c = 3 in EntryC-1, we find that<br />

and<br />

a = bc +1+� (b 2 − 1) (c 2 − 1)<br />

b + c<br />

r0 = bc − 1 − � (b 2 − 1) (c 2 − 1)<br />

c − b<br />

= 7+2√6 ,<br />

5<br />

=5− 2 √ 6.<br />

Thus, the domain D is mapped onto the annulus 5 − 2 √ 6

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