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Complex Analysis - Maths KU

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7.2 Linear Fractional Transformations 405<br />

A −1 ⎛ ⎞<br />

a<br />

= ⎝<br />

b<br />

⎠<br />

c d<br />

Byidentifying e =<br />

matrix<br />

−1<br />

=<br />

⎛<br />

1<br />

⎝<br />

ad − bc<br />

d −b<br />

⎞<br />

⎠ .<br />

−c a<br />

1<br />

ad − bc in (8) we can also represent T −1 (z) bythe<br />

⎛ ⎞<br />

⎝<br />

d −b<br />

⎠ .<br />

−c a<br />

∗ (10)<br />

EXAMPLE 4 Using Matrices<br />

Suppose S(z) =(z− i)/ (iz − 1) and T (z) =(2z−1)/ (z + 2). Use matrices<br />

to find S−1 (T (z)).<br />

Solution We represent the linear fractional transformations S and T bythe<br />

matrices<br />

⎛ ⎞ ⎛ ⎞<br />

1<br />

⎝<br />

−i<br />

⎠ and<br />

2<br />

⎝<br />

−1<br />

⎠,<br />

i −1<br />

1 2<br />

respectively. By (10), the transformation S−1 is given by<br />

⎛ ⎞<br />

−1<br />

⎝<br />

i<br />

⎠,<br />

−i 1<br />

and so, from (9), the composition S−1 ◦ T is given by<br />

⎛ ⎞ ⎛ ⎞ ⎛<br />

⎞<br />

−1<br />

⎝<br />

i 2<br />

⎠ ⎝<br />

−1 −2+i<br />

⎠ = ⎝<br />

1+2i<br />

⎠<br />

−i 1 1 2 1 − 2i 2+i<br />

Therefore,<br />

S −1 (T (z)) =<br />

(−2+i) z +1+2i<br />

(1 − 2i) z +2+i .<br />

Cross-Ratio In applications we often need to find a conformal mapping<br />

from a domain D that is bounded bycircles onto a domain D ′ that is bounded<br />

bylines. Linear fractional transformations are particularlywell-suited for such<br />

applications. However, in order to use them, we must determine a general<br />

∗ You may recall that this matrix is called the adjoint matrix of A.

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