14.12.2012 Views

Complex Analysis - Maths KU

Complex Analysis - Maths KU

Complex Analysis - Maths KU

SHOW MORE
SHOW LESS

You also want an ePaper? Increase the reach of your titles

YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.

298 Chapter 5 Integration in the <strong>Complex</strong> Plane<br />

19. If p(z) is a polynomial in z then the function f(z) =1/p(z) can be never be an<br />

entire function.<br />

20. The function f(z) = cos z is entire and not a constant and so must be unbounded.<br />

In Problems 21–40, try to fill in the blanks without referring back to the text.<br />

21. z(t) =e it2<br />

, 0 ≤ t ≤ √ 2π, is a parametrization for a .<br />

22. z(t) =z0 + e it , 0 ≤ t ≤ 2π, is a parametrization for a .<br />

23. The difference between z1(t) =e it , 0 ≤ t ≤ 2π and z2(t) =e i(2π−t) , 0 ≤ t ≤ 2π<br />

is<br />

�<br />

.<br />

24. (2y + x − 6ix 2 ) dz = , where C is the triangle with vertices 0, i,<br />

C<br />

1+i, traversed counterclockwise.<br />

25. �If<br />

f is a polynomial function and C is a simple closed contour, then<br />

f(z) dz = .<br />

26.<br />

27.<br />

28.<br />

29.<br />

30.<br />

�<br />

�<br />

�<br />

�<br />

�<br />

C<br />

C<br />

C<br />

C<br />

C<br />

C<br />

z Im(z) dz = , where C is given by z(t) =2t + t 2 i, 0 ≤ t ≤ 1.<br />

|z| 2 dz = , where C is the line segment for 1 − i to 1 + i.<br />

(¯z) n dz = , where n is an integer and C is z(t) =e it , 0 ≤ t ≤ 2π.<br />

sin z<br />

2 dz = , where C is given by z(t) =2i +4eit , 0 ≤ t ≤ π/2.<br />

sec zdz= , where C is |z| =1.<br />

�<br />

1<br />

31.<br />

C z(z − 1)<br />

�<br />

32. If f(z) =<br />

C<br />

dz = , where C is |z − 1| = 1<br />

2 .<br />

ξ 2 +6ξ − 2<br />

ξ − z<br />

dξ, where C is |z| = 3, then f(1 + i) = .<br />

33. If f(z) = z 3 + e z and C is a contour z = 8e it �<br />

, 0 ≤ t ≤ 2π, then<br />

f(z)<br />

dz = .<br />

C (z + πi) 3<br />

��<br />

�<br />

� �<br />

34. If | f(z) |≤2 on the circle |z| =3, then �<br />

� f(z) dz �<br />

� ≤ .<br />

35. �If<br />

n is a positive integer and C is the contour |z| = 2, then<br />

z −n e z dz = .<br />

C<br />

�<br />

cos z<br />

36. On |z| = 1, the contour integral dz equals<br />

C zn for n = 2, and equals for n =3.<br />

for n = 1, equals<br />

37.<br />

�<br />

z<br />

C<br />

n ⎧<br />

⎨ 0,<br />

dz =<br />

⎩ 2πi,<br />

|z| =1.<br />

if n<br />

if n<br />

, where n is an integer and C is the circle<br />

C

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!