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Complex Analysis - Maths KU

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5.2 <strong>Complex</strong> Integrals 245<br />

In Problems 29 and 30, evaluate �<br />

29. 30.<br />

y<br />

(–1, 1)<br />

(–1, –1)<br />

(1, 1)<br />

(1, –1)<br />

x<br />

C x2 y 3 dx − xy 2 dy on the given closed curve.<br />

Figure 5.13 Figure for Problem 29<br />

Figure 5.14 Figure for Problem 30<br />

31. Evaluate � � 2 2<br />

x − y C<br />

� ds, where C is given by x = 5 cos t, y = 5 sin t, 0≤ t ≤ 2π.<br />

32. Evaluate �<br />

ydx−xdy, where C is given by x = 2 cos t, y = 3 sin t, 0 ≤ t ≤ π.<br />

−C<br />

33. Verify that the line integral �<br />

C y2 dx + xy dy has the same value on C for each<br />

of the following parametrizations:<br />

y<br />

(2, 4)<br />

C : x =2t +1, y =4t +2, 0 ≤ t ≤ 1<br />

C : x = t 2 , y =2t 2 , 1 ≤ t ≤ √ 3<br />

C : x =lnt, y =2lnt, e ≤ t ≤ e 3 .<br />

34. Consider the three curves between (0, 0) and (2, 4):<br />

Show that �<br />

C1<br />

C : x = t, y =2t, 0 ≤ t ≤ 2<br />

C : x = t, y = t 2 , 0 ≤ t ≤ 2<br />

C : x =2t− 4, y =4t− 8, 2 ≤ t ≤ 3.<br />

�<br />

� �<br />

xy ds = xy ds, but xy ds �= xy ds. Explain.<br />

C3<br />

35. If ρ(x, y) is the density of a wire (mass per unit length), then the mass of<br />

the wire is m = �<br />

ρ(x, y) ds. Find the mass of a wire having the shape of<br />

C<br />

a semicircle x = 1 + cos t, y = sin t, 0 ≤ t ≤ π, if the density at a point P is<br />

directly proportional to the distance from the y-axis.<br />

36. The coordinates of the center of mass of a wire with variable density are given<br />

by ¯x = My/m, ¯y = Mx/m where<br />

�<br />

�<br />

�<br />

m = ρ(x, y) ds, Mx = yρ(x, y) ds, My = xρ(x, y) ds.<br />

5.2 <strong>Complex</strong> Integrals<br />

C<br />

Find the center of mass of the wire in Problem 35.<br />

In the preceding 5.2 section we reviewed two types of real integrals. We saw that the definition<br />

of the definite integral starts with a real function y = f(x) that is defined on an interval on<br />

the x-axis. Because a planar curve is the two-dimensional analogue of an interval, we then<br />

generalized the definition of � b<br />

f(x) dx to integrals of real functions of two variables defined<br />

a<br />

on a curve C in the Cartesian plane. We shall see in this section that a complex integral is<br />

defined in a manner that is quite similar to that of a line integral in the Cartesian plane.<br />

Since curves play a big part in the definition of a complex integral, we begin with a<br />

brief review of how curves are represented in the complex plane.<br />

C<br />

C1<br />

C2<br />

x<br />

C

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