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Complex Analysis - Maths KU

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142 Chapter 3 Analytic Functions<br />

3.1 Differentiability and Analyticity<br />

The calculus of3.1 complex functions deals with the usual concepts of derivatives and integrals<br />

of these functions. In this section we shall give the limit definition of the derivative of a<br />

complex function f(z). Although many of the concepts in this section will seem familiar to<br />

you, such as the product, quotient, and chain rules of differentiation, there are important<br />

differences between this material and the calculus of real functions f(x). As the subsequent<br />

chapters of this text unfold, you will see that except for familiarity of names and definitions,<br />

there is little similarity between the interpretations of quantities such as f ′ (x) and f ′ (z).<br />

The Derivative Suppose z = x+iy and z0 = x0+iy0; then the change<br />

in z0 is the difference ∆z = z − z0 or ∆z = x − x0 + i(y − y0) =∆x + i∆y. If<br />

a complex function w = f(z) is defined at z and z0, then the corresponding<br />

change in the function is the difference ∆w = f(z0 +∆z) − f(z0). The<br />

derivative of the function f is defined in terms of a limit of the difference<br />

quotient ∆w/∆z as ∆z → 0.<br />

Definition 3.1 Derivative of <strong>Complex</strong> Function<br />

Suppose the complex function f is defined in a neighborhood of a point<br />

z0. The derivative of f at z0, denoted by f ′ (z0), is<br />

provided this limit exists.<br />

f ′ f(z0 +∆z) − f(z0)<br />

(z0) = lim<br />

∆z→0 ∆z<br />

If the limit in (1) exists, then the function f is said to be differentiable<br />

at z0. Two other symbols denoting the derivative of w = f(z) are w ′ and<br />

dw/dz. If the latter notation is used, then the value of a derivative at a<br />

specified point z0 is written dw<br />

�<br />

�<br />

� .<br />

dz<br />

� z=z0<br />

EXAMPLE 1 Using Definition 3.1<br />

Use Definition 3.1 to find the derivative of f(z) =z 2 − 5z.<br />

Solution Because we are going to compute the derivative of f at any point,<br />

we replace z0 in (1) by the symbol z. First,<br />

f(z +∆z) =(z +∆z) 2 − 5(z +∆z) =z 2 +2z∆z +(∆z) 2 − 5z − 5∆z.<br />

Second,<br />

f(z +∆z) − f(z) =z 2 +2z∆z +(∆z) 2 − 5z − 5∆z − (z 2 − 5z)<br />

=2z∆z +(∆z) 2 − 5∆z.<br />

(1)

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