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The Delft Sand, Clay & Rock Cutting Model, 2019a

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<strong>The</strong> <strong>Delft</strong> <strong>Sand</strong>, <strong>Clay</strong> & <strong>Rock</strong> <strong>Cutting</strong> <strong>Model</strong>.<br />

8.3.1. <strong>The</strong> <strong>Model</strong> of Evans.<br />

For brittle rock the cutting theory of Evans (1964) and (1966) can be used to calculate cutting forces (Figure<br />

8-21). <strong>The</strong> forces are derived from the geometry of the chisel (width, cutting angle and cutting depth) and the<br />

tensile strength (BTS) of the rock. Evans suggested a model on basis of observations on coal breakage by wedges.<br />

In this theory it is assumed that:<br />

1. A force R is acting under an angle δ (external friction angle) with the normal to the surface A-C of the wedge.<br />

2. A resultant force T of the tensile stresses acting at the center of the arc C-D, the line C-D is under an angle β<br />

(the shear angle) with the horizontal.<br />

3. A third force S is required to maintain equilibrium in the buttock, but does not play a role in the derivation.<br />

4. <strong>The</strong> penetration of the wedge is small compared to the layer thickness hi.<br />

<strong>The</strong> action of the wedge tends to split the rock and does rotate it about point D. It is therefore assumed that the<br />

force S acts through point D. Along the fracture line, it is assumed that a state of plain strain is working and the<br />

equilibrium is considered per unit of width w of the wedge.<br />

<strong>The</strong> force due to the tensile strength σT of the rock is:<br />

T<br />

<br />

T <br />

(8-41)<br />

<br />

T r cos d w 2 r sin w<br />

Where r·d is an element of the arc C-D making an angle with the symmetry axis of the arc. Let hi be the depth<br />

of the cut and assume that the penetration of the edge may be neglected in comparison with hi. This means that the<br />

force R is acting near point C. Taking moments on the chip cut about point D gives:<br />

hi<br />

R cos <br />

T r sin 2 T<br />

r sin w r sin <br />

sin<br />

<br />

<br />

(8-42)<br />

From the geometric relation it follows:<br />

<br />

h i<br />

r sin (8-43)<br />

2sin <br />

Hence:<br />

<br />

T hi<br />

w<br />

R (8-44)<br />

2sin cos<br />

<br />

<br />

<strong>The</strong> horizontal component of R is R·sin(α+δ) and due to the symmetry of the forces acting on the wedge the total<br />

cutting force is:<br />

<br />

c T i<br />

<br />

sin<br />

<br />

<br />

<br />

F 2 Rsin h w<br />

sin cos<br />

(8-45)<br />

<strong>The</strong> normal force ( on cutting force) is per side:<br />

<br />

<br />

Fn Rcos Thi w<br />

2sin cos<br />

cos <br />

<br />

<br />

(8-46)<br />

<strong>The</strong> angle β can be determined by using the principle of minimum energy:<br />

dF c<br />

d<br />

0<br />

(8-47)<br />

Giving:<br />

Page 262 of 454 TOC Copyright © Dr.ir. S.A. Miedema

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