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The Delft Sand, Clay & Rock Cutting Model, 2019a

The Delft Sand, Clay & Rock Cutting Model, 2019a

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A Wedge in <strong>Clay</strong> <strong>Cutting</strong>.<br />

Figure 13-4: <strong>The</strong> forces on the blade when cutting clay with a wedge.<br />

13.3. <strong>The</strong> Equilibrium of Moments.<br />

<strong>The</strong> first additional condition is the equilibrium of moments of the wedge. Since the wedge is not subject to<br />

rotational accelerations in a stationary cutting process, the sum of the moments around any point on the wedge has<br />

to be zero. Here the tip of the blade is chosen for this point. First the equilibrium of moments is solved in order to<br />

find a relation between N3 and N4.<br />

Figure 13-5: <strong>The</strong> equilibrium of moments on the wedge when cutting clay.<br />

To solve the equilibrium of moments the lengths of the sides of the wedge and arms of the forces have to be<br />

determined.<br />

<strong>The</strong> length of the shear plane A-B is:<br />

L<br />

1<br />

h<br />

<br />

sin<br />

i<br />

<br />

(13-16)<br />

Copyright © Dr.ir. S.A. Miedema TOC Page 381 of 454

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