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The Delft Sand, Clay & Rock Cutting Model, 2019a

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Basic Soil Mechanics.<br />

2.8. <strong>The</strong> Mohr Circle.<br />

In the derivation of the Mohr circle the vertical stress σv and the horizontal stress σh are assumed to be the principal<br />

stresses, but in reality these stresses could have any orientation. It should be noted here that the Mohr circle<br />

approach is valid for the stress situation in a point in the soil. Now consider an infinitesimal element of soil under<br />

plane strain conditions as is shown in Figure 2-44. On the element a vertical stress σv and a horizontal stress σh are<br />

acting. On the horizontal and vertical planes the shear stresses are assumed to be zero. Now the question is, what<br />

would the normal stress σ and shear stress τ be on a plane with an angle α with the horizontal direction? To solve<br />

this problem, the horizontal and vertical equilibriums of forces will be derived. Equilibriums of stresses do not<br />

exist. One should consider that the surfaces of the triangle drawn in Figure 2-44 are not equal. If the surface (or<br />

length) of the surface under the angle α is considered to be 1, then the surface (or length) of the horizontal side is<br />

cos(α) and the vertical side sin(α). <strong>The</strong> stresses have to be multiplied with their surface in order to get forces and<br />

forces are required for the equilibriums of forces, see Figure 2-45. <strong>The</strong> derivation of the Mohr circle is also an<br />

exercise for the derivation of many equations in this book where equilibriums of forces and moments are applied.<br />

Figure 2-44: <strong>The</strong> stresses on a soil element.<br />

Figure 2-45: <strong>The</strong> forces on a soil element.<br />

Since an equilibrium of stresses does not exist, only an equilibrium of forces exists, the forces on the soil element<br />

have to be known, or the ratio of the forces has to be known.<br />

<strong>The</strong>se forces are, assuming the length of the side under an angle α is 1:<br />

<br />

h h v v<br />

<br />

F sin and F cos<br />

(2-45)<br />

And:<br />

F and F (2-46)<br />

n<br />

s<br />

<strong>The</strong> equilibrium of forces in the horizontal direction:<br />

Copyright © Dr.ir. S.A. Miedema TOC Page 55 of 454

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