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The Delft Sand, Clay & Rock Cutting Model, 2019a

The Delft Sand, Clay & Rock Cutting Model, 2019a

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<strong>The</strong> <strong>Delft</strong> <strong>Sand</strong>, <strong>Clay</strong> & <strong>Rock</strong> <strong>Cutting</strong> <strong>Model</strong>.<br />

16.6.6. Calc.: Permeability.<br />

What is the value of the mean permeability km as used in the cutting equations for water saturated sand?<br />

Consider a sand with the following properties:<br />

Initial permeability: k i=0.0001 m/sec<br />

Maximum permeability: k max=0.0004 m/sec<br />

ki<br />

kmax<br />

0.0001<br />

0.0004<br />

km<br />

0.00025 (m/sec)<br />

2 2<br />

16.6.7. Calc.: Dilatancy.<br />

What is the value of the dilatancy ε?<br />

Consider a sand with the following properties:<br />

initial porosity: n i=40%<br />

Maximum porosity: n max=50%<br />

nmax<br />

ni<br />

0.5 0.4<br />

0.20<br />

1<br />

n 1<br />

0.5<br />

max<br />

(-)<br />

16.6.8. Calc.: Transition Velocity.<br />

Give the equation for the transition velocity from non-cavitating cutting to cavitating cutting.<br />

v<br />

c<br />

<br />

d z 10 k<br />

<br />

c h<br />

<br />

<br />

1 m<br />

1 i<br />

16.6.9. Calc.: <strong>Cutting</strong> Forces & Specific Energy.<br />

Consider a sand with the following properties:<br />

Angle of internal friction: φ=36º<br />

Angle of external friction: δ=24º<br />

Initial permeability: k i=0.00005 m/sec<br />

Maximum permeability: k max=0.00025 m/sec<br />

initial porosity: n i=42%<br />

Maximum porosity: n max=50%<br />

<strong>The</strong> cutting blade has the following properties:<br />

<strong>The</strong> cutting angle: α=60º<br />

<strong>The</strong> shear angle: β=20º<br />

<strong>The</strong> blade height: h b=0.2 m<br />

<strong>The</strong> thickness of the layer to be cut: h i=0.1 m<br />

<strong>The</strong> width of the blade: w=1 m<br />

Coefficients for the cutting equations:<br />

<strong>The</strong> coefficient for non-cavitating cutting: c 1=0.35<br />

<strong>The</strong> coefficient for cavitating cutting: d 1=4.5<br />

General constants:<br />

<strong>The</strong> density of water: ρ w=1.025 tons/m 3<br />

<strong>The</strong> gravitational constant: g=9.81 m/sec 2<br />

A: What are the horizontal cutting forces at 0 m, 15 m and 30 m water depth for the non-cavitational cutting<br />

process at a cutting velocity of 0.5 m/s?<br />

Page 410 of 454 TOC Copyright © Dr.ir. S.A. Miedema

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