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McKay, Donald. "Front matter" Multimedia Environmental Models ...

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We can also relate equilibrium concentrations in these phases using the three Z<br />

values and fugacity. The partition coefficients are simply the ratio of the respective<br />

Z values; e.g., K AW is Z A/Z W. The use of Z values at this stage brings little benefit,<br />

but they become very useful when we calculate partitioning to environmental media.<br />

We use Z A, Z W, and Z O to calculate Z in phases such as soils, sediments, fish, and<br />

aerosol particles, and it proves useful to have Z P as a reference point when examining<br />

the magnitude of Z values. It is enlightening to calculate all the physical chemical<br />

properties of a solid and a liquid substance as shown in the following example.<br />

Worked Example 5.3<br />

Deduce all relevant thermodynamic air-water partitioning properties for benzene<br />

(liquid) and naphthalene (a solid of melting point 80°C) at 25°C.<br />

Benzene<br />

Vapor pressure = 12700 Pa (P S L), molar mass = 78 g/mol, solubility in water =<br />

1780 g/m 3 .<br />

©2001 CRC Press LLC<br />

Z A = 1/RT = 1/(8.314 ¥ 298) = 4.04 ¥ 10 –4<br />

Solubility C S L = 1780/78 = 22.8 mol/m 3<br />

Activity coefficient g = 1/v wC S L = 1/(18 ¥ 10 –6 ¥ 23.1) = 2440<br />

Naphthalene<br />

H = P S L/C S L = 556, also = v WgP S L<br />

Z W = 1/H or 1/v wgP S L = 0.0018<br />

K AW = H/RT or Z A/Z W = 0.22<br />

Solubility = 33 g/m 3 , molar mass = 128 g/mol, vapor pressure = 10.9 Pa<br />

Z A = 4.04 ¥ 10 –4 as before<br />

F = exp(–6.79(353/298–1)) = 0.286 (mp = 353 K)<br />

P S L = P S S/F = 38.1<br />

C S S = 33/128 = 0.26 mol/m 3 , C S L = 0.90 mol/m 3<br />

g = 1/v wC S L = 61700<br />

H = P S S /C S S or P S L/C S L = 42<br />

Z W = 1/H or 0.024 = 1/v wgP S L<br />

K AW = H/RT or Z A/Z W = 0.017<br />

Note that naphthalene has a higher activity coefficient corresponding to its lower<br />

solubility and greater hydrophobicity.

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