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McKay, Donald. "Front matter" Multimedia Environmental Models ...

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Integrating from an initial condition of C O at zero time gives the following<br />

equations:<br />

©2001 CRC Press LLC<br />

ln(C/C O) = –kt or C = C O exp(–kt)<br />

Rate constants have units of frequency or reciprocal time and are therefore not<br />

easily grasped or remembered. A favorite trick question of examiners is to ask a<br />

student to convert a rate constant of 24 h –1 into reciprocal days. The correct answer<br />

is 576 days –1 , so beware of this conversion! It is more convenient to store and<br />

remember half-lives, i.e., the time, t 1/2, which is the time required for C to decrease<br />

to half of C O. This can be related to the rate constant as follows.<br />

When C = 0.5 C O, then t = t 1/2<br />

ln (0.5) = –kt 1/2, therefore, t 1/2 = 0.693/k<br />

For example, an isotope with a half-life of 10 hours has a rate constant, k, of<br />

0.0693 h –1 .<br />

6.3.2 Non-First-Order Kinetics<br />

Unfortunately, there are many situations in which the real reaction rate is not a<br />

first-order reaction. Second-order rate reactions occur when the reaction rate is<br />

dependent on the concentration of two chemicals or reactants. For example, if<br />

A + B Æ D + E<br />

then the rate of the reaction is dependent on the concentration of both A and B.<br />

Therefore, the reaction rate is as follows:<br />

N = Vk C A C B<br />

Reactant “B” is often another chemical, but it could be another environmental<br />

reactant such as a microbial population or solar radiation intensity. Third-order<br />

reaction rates, when the rate of reaction is dependent on the concentration of three<br />

reactants (N = Vk C A C B C C), are very rare and are unlikely to occur under environmental<br />

conditions.<br />

We can often circumvent these complex reaction rate equations by expressing<br />

them in terms of a pseudo first-order rate reaction. The primary assumption is that<br />

the concentration of reactant “B” is effectively constant and will not change appreciably<br />

as the reaction proceeds. Thus, the constant k and concentration of reactant<br />

“B” can be lumped into a new rate constant, k P, and the second-order reaction<br />

becomes a pseudo first-order reaction. Therefore,<br />

N = Vk C AC B

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