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McKay, Donald. "Front matter" Multimedia Environmental Models ...

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1. Fallout of chemical from air to water or soil in dustfall, rain, or snow<br />

2. Deposition of chemical from water to sediments in association with suspended<br />

matter which deposits on the bed of sediment<br />

3. The reverse process of resuspension<br />

4. Ingestion and egestion of food containing chemical by biota<br />

The mathematical expressions for these rates are quite different. For diffusion,<br />

the net rate of transfer or flux is written as the product of the departure from<br />

equilibrium and a kinetic quantity, and the net flux becomes zero when the phases<br />

are in equilibrium. We examine these diffusive processes in Chapter 7. For nondiffusive<br />

processes, the flux is the product of the volume of the phase transferred (e.g.,<br />

quantity of sediment or rain) and the concentration. We treat nondiffusive processes<br />

in Chapter 6.<br />

We use the word flux as short form for transport rate. It has units such as mol/h<br />

or g/h. Purists insist that flux should have units of mol/h·m 2 , i.e., it should be area<br />

specific. We will apply it to both. It is erroneous to use the term flux rate since flux,<br />

like velocity, already contains the “per time” term.<br />

©2001 CRC Press LLC<br />

2.8 RESIDENCE TIMES AND PERSISTENCE<br />

In some environments, such as lakes, it is convenient to define a residence time<br />

or detention time. If a pond has a volume of 1000 m 3 and experiences inflow and<br />

outflow of 2 m 3 /h, it is apparent that, on average, the water spends 500 h (20.8 days)<br />

(i.e., 1000 m 3 /2 m 3 /h) in the lake. This residence or detention time may not bear<br />

much relationship to the actual time that a particular parcel of water spends in the<br />

pond, since some water may bypass most of the pond and reside for only a short<br />

time, and some may be trapped for years. The quantity is very useful, however,<br />

because it gives immediate insight into the time required to flush out the contents.<br />

Obviously, a large lake with a long residence time will be very slow to recover from<br />

contamination. Comparison of the residence time with a chemical reaction time (e.g.,<br />

a half-life) indicates whether a chemical is removed from a lake predominantly by<br />

flow or by reaction.<br />

If a well mixed lake has a volume V m 3 and equal inflow and outflow rates G<br />

m 3 /h, then the flow residence time t F is V/G (h). If it is contaminated by a nonreacting<br />

(conservative) chemical at a concentration C O mol/m 3 at zero time and there is no<br />

new emission, a mass balance gives, as was shown earlier,<br />

C = C 0 exp(–Gt/V) = C 0 exp (–t/t F) = C O exp(–k F t)<br />

The residence time is thus the reciprocal of a rate constant k F with units of h –1 . The<br />

half-time for recovery occurs when t/t F or k Ft is ln 2 or 0.693, i.e., when t is 0.693t<br />

or 0.693/k.<br />

If the chemical also undergoes a reaction with a rate constant k R h –1 , it can be<br />

shown that<br />

C = C 0 exp[–(k F + k R)t] = C 0 exp(–k Tt)

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