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McKay, Donald. "Front matter" Multimedia Environmental Models ...

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access to information about the stability of the crystalline state, i.e., does not<br />

“know” its melting point. As a result, it behaves in a manner corresponding to the<br />

liquid vapor pressure. A similar phenomenon occurs above the critical point where<br />

a gas such as oxygen, when in solution in water, behaves as if it were a liquid at<br />

25°C, not a gas. No liquid vapor pressure can be measured for either naphthalene<br />

or oxygen at 25°C; it can only be calculated. Later, we term this liquid vapor<br />

pressure the reference fugacity. We may need to know this fictitious vapor pressure<br />

for several reasons.<br />

The ratio of the solid vapor pressure to the supercooled liquid vapor pressure is<br />

termed the fugacity ratio, F. To estimate F, we need to know how much energy is<br />

involved in the solid-liquid transition, i.e., the enthalpy of melting or fusion. The<br />

rigorous equation for estimating F at temperature T(K) is (Prausnitz et al., 1986)<br />

©2001 CRC Press LLC<br />

ln F = – DS(TM<br />

– T)/RT + DCP(TM<br />

– T)/RT – DCP<br />

ln(TM/T)/R<br />

where DS<br />

(J/mol K) is the entropy of fusion at the melting point TM<br />

(K), DCP<br />

(J/mol<br />

K) is the difference in heat capacities between the solid and liquid substances, and<br />

R is the gas constant. The heat capacity terms are usually small, and they tend to<br />

cancel, so the equation can be simplified to<br />

ln F = – DS(TM<br />

– T)/RT = –( DH/TM)(TM<br />

– T)/RT = –( DH/R)(1/T<br />

– 1/TM)<br />

where DH<br />

(J/mol) is the enthalpy of fusion and equals TMDS.<br />

Note that, since TM<br />

is greater than T, the right-hand side is negative, and F is<br />

less than one, except at the melting point, when it is 1.0. F can never exceed 1.0. A<br />

convenient method of estimating DH<br />

is to exploit Walden’s rule that the entropy of<br />

fusion at the melting point DS,<br />

which is DH/TM,<br />

is often about 56.5 J/mol K. It<br />

follows that<br />

The group<br />

mated as<br />

ln F = –(DS/R)(TM/T<br />

– 1)<br />

DS/R<br />

is often assigned a value of 56/8.314 or 6.79. Thus, F is approxi-<br />

F = exp[–6.79(TM/T<br />

– 1)]<br />

If base 10 logs are used and T is 298 K, this equation becomes<br />

log F = –6.79(TM/298<br />

– 1)/2.303 = –0.01(TM<br />

– 298)<br />

This is useful as a quick and easily remembered method of estimating F. If more<br />

accurate data are available for DH<br />

or DS,<br />

they should be used, and if the substance<br />

is a high melting point solid, it may be advisable to include the heat capacity terms.

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