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McKay, Donald. "Front matter" Multimedia Environmental Models ...

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Worked Example 2.1<br />

A three-phase system consists of air (100 m3),<br />

water (60 m3),<br />

and sediment (3<br />

m3).<br />

To this is added 2 mol of a hydrocarbon such as benzene. The phase volumes<br />

are not affected by this addition, because the volume of hydrocarbon is small.<br />

Subscripting air, water, and sediment symbols with A, W, and S, respectively, and<br />

designating volume as V (m3)<br />

and concentration as C (mol/m3),<br />

we can write the<br />

mass balance equation.<br />

©2001 CRC Press LLC<br />

total amount = sum of amounts in each phase mol<br />

2 = VACA<br />

+ VWCW<br />

+ VSCS = 100 CA + 60 CW + 3 CS mol<br />

To proceed further, we must have information about the relationships between C A,<br />

C W, and C S. This could take the form of phase equilibrium equations such as<br />

C A/C W = 0.4 and C S/C W = 100<br />

These ratios are usually referred to as partition coefficients or distribution coefficients<br />

and are designated K AW and K SW, respectively. We discuss them in more<br />

detail later.<br />

We can now eliminate C A and C S by substitution to give<br />

Thus,<br />

It follows that<br />

2 = 100 (0.4 C W) + 60 C W + 3(100C W) = 400 C W mol<br />

C W = 2/400 = 0.005 mol/m 3<br />

C A = 0.4 C W = 0.002 mol/m 3<br />

C S = 100 C W = 0.5 mol/m 3<br />

The amounts in each phase (m i) mol are the VC products as follows:<br />

mW = VWCW = 0.30 mol (15%)<br />

mA = VACA = 0.20 mol (10%)<br />

mS = VSCS = 1.50 mol (75%)<br />

Total 2.00 mol<br />

This simple algebraic procedure has established the concentrations and amounts in<br />

each phase using a closed system, steady-state, mass balance equation and equilibrium<br />

relationships. The essential concept is that the total amount of chemical present

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