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McKay, Donald. "Front matter" Multimedia Environmental Models ...

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Mackay (1986), in an attempt to simplify this correlation, forced m to be –1 and<br />

obtained a one-parameter equation, using the liquid vapor pressure,<br />

©2001 CRC Press LLC<br />

K QA = 6 ¥ 10 6 /P S L<br />

where K QA is a dimensionless partition coefficient, i.e., a ratio of (mol/m 3 )/(mol/m 3 ),<br />

and P S L has units of Pascals. Here, we use subscript Q to designate the aerosol phase.<br />

This enables Z Q, the Z value of the chemical in the aerosol particle, to be estimated<br />

as K QAZ A. It can be shown that K QA is 10 12 K P(r/1000) where r is the density of<br />

the aerosol (kg/m 3 ), i.e., typically 1500 kg/m 3 . The 10 12 derives from the conversion<br />

of µg to Mg. The fraction on the aerosol j can then be calculated as<br />

j = K QA v Q/(1 + K QA v Q)<br />

where v Q is the volume fraction of aerosol and is 10 –12 TSP/(r/1000) when TSP has<br />

units of mg/m 3 . TSP is typically about 30 mg/m 3 , plus or minus a factor of 5; thus,<br />

v Q is about 20 ¥ 10 –12 , plus or minus the same factor. Equipartitioning between air<br />

and aerosol phases occurs when j is 0.5 or K P·TSP and K QAv Q equals 1.0. This<br />

implies a chemical with a K P of 0.03 m 3 /mg or K QAof 0.05 ¥ 10 12 and a vapor pressure<br />

of about 10 –4 Pa.<br />

It is noteworthy that Z Q has a value of K QAZ A or about (6 ¥ 10 6 /P S L)(4 ¥ 10 –4 )<br />

or 2400/P S L. This is comparable to Z P, the pure substance Z value of 1/v P S L, where<br />

v is the chemical’s molar volume and is typically 100 cm 3 /mol or 10 –4 m 3 /mol, giving<br />

a Z P of about 10,000/P S L. This implies that the solute is behaving near-ideally in the<br />

aerosol, i.e., the solubility in the aerosol is about 24% of the solubility of a substance<br />

in itself. This casts doubt on the surface sorption model, since it seems a remarkable<br />

coincidence that the area is such that it gives this near-ideal behavior. It further<br />

suggests that Z Q may correlate well with Z O for octanol.<br />

This was explored by Finizio et al. (1997), Bidleman and Harner (2000), and<br />

Pankow (1998), leading ultimately to a suggestion that<br />

K P = 10 –12 K OA y (1000/820) = 10 –11.91 K OA y<br />

where 820 kg/m 3 is the density of octanol, and y is the fraction organic matter in<br />

the aerosol, which is typically 0.2.<br />

This reduces to<br />

K P = 10 –12.61 K OA or 0.25 ¥ 10 –12 K OA m 3 /mg<br />

the use of K OA is advantageous, because it eliminates the need to deduce the fugacity<br />

ratio, F, when calculating the subcooled liquid vapor pressure. It is also possible<br />

that, for a series of chemicals, the activity coefficients in octanol and aerosol organic<br />

matter are similar, or at least have a fairly constant ratio.<br />

This approach is appealing, because it mimics the Karickhoff method of calculating<br />

soil-water partitioning, except that partitioning is now to air instead of water;<br />

thus, K OA replaces K OW.

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