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HEMISKI Zbirka re{eni zada~i REAKTORI 3

HEMISKI Zbirka re{eni zada~i REAKTORI 3

HEMISKI Zbirka re{eni zada~i REAKTORI 3

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) Za adijabatska rabota na serijata }e bide pot<strong>re</strong>ben<br />

i toplinskiot bilans, ravenkata (129):<br />

~<br />

0 , ( T T ) ( H<br />

)( r<br />

) V . (129)<br />

148<br />

smesaC<br />

P smesa o<br />

r A<br />

Ravenkata (129) kombinirana so ravenkata za dizajn (1),<br />

Vi<br />

FAo<br />

X i X i1<br />

,<br />

( rA<br />

) i<br />

(1)<br />

}e ja dade ravenkata:<br />

~<br />

smesaC<br />

P,<br />

smesa ( T<br />

) i ( H<br />

r ) FAo<br />

( X<br />

) i . (4)<br />

Vo ravenkata (4) gi zamenuvame numeri~kite v<strong>re</strong>dnosti za<br />

poznatite veli~ini,<br />

F / C<br />

3 ~<br />

1 kmol/m ; C<br />

6 3<br />

4,<br />

2 10<br />

J/(m K) ;<br />

Ao<br />

o<br />

( T<br />

)<br />

i<br />

Ao<br />

( H<br />

~<br />

C<br />

r<br />

P,<br />

smesa<br />

)<br />

( X<br />

)<br />

i<br />

P,<br />

smesa<br />

1,<br />

67 10<br />

( X<br />

) ;<br />

6 i<br />

4,<br />

2 10<br />

i<br />

i<br />

P<strong>re</strong>smetkata ponatamu podrazbira kombinirawe na ravenkite<br />

(2) i (5) za sekoj <strong>re</strong>aktor vo serijata. No bidej}i e postaven<br />

uslovot izleznata temperatura od sekoj <strong>re</strong>aktor da bide kolku<br />

{to e dozvolenata, Tizlez=95 o C, toga{ namesto ravenkata (2) za<br />

sekoj <strong>re</strong>aktor }e se prim<strong>eni</strong> ravenkata (3) (kako vo izotermnata<br />

serija). Ostanuva od ravenkata (5) da se p<strong>re</strong>smeta kakva mora da<br />

bide vleznata temperatura vo sekoj od <strong>re</strong>aktorite:<br />

prviot <strong>re</strong>aktor:<br />

( T<br />

)<br />

1<br />

1<br />

95 T<br />

o<br />

1,<br />

o<br />

6<br />

( T ) 39,<br />

76 ( X<br />

) . (5)<br />

T T<br />

1<br />

T 95 C;<br />

X<br />

<br />

1,<br />

o<br />

1<br />

39,<br />

76<br />

vtoriot <strong>re</strong>aktor:<br />

( T<br />

)<br />

T<br />

2<br />

2<br />

95<br />

95 T<br />

T<br />

o<br />

2,<br />

o<br />

2<br />

C;<br />

T<br />

X<br />

2<br />

39,<br />

76(<br />

0,<br />

533;<br />

<br />

2,<br />

o<br />

<br />

0,<br />

533<br />

<br />

0,<br />

78;<br />

<br />

X<br />

1<br />

1<br />

T<br />

39,<br />

76(<br />

X<br />

X<br />

<br />

1,<br />

o<br />

2<br />

<br />

0)<br />

;<br />

<br />

73,<br />

8<br />

X ) ;<br />

1<br />

0,<br />

533<br />

39,<br />

76(<br />

0,<br />

78 0,<br />

533)<br />

T<br />

;<br />

o<br />

2,<br />

o<br />

C;<br />

o<br />

85,<br />

18 C;

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