HEMISKI Zbirka re{eni zada~i REAKTORI 3

POLYMATH Results
Calculated values of the DEQ variables
Variable initial value minimal value maximal value final value
V 0 0 10 10
Fe 0.00344 0.0016469 0.00344 0.0016469
Fs 0 0 0.0017931 0.0017931
Fh 0 0 0.0017931 0.0017931
T 900 830.56731 900 830.56731
deltaH1 1.18E+05 1.18E+05 1.18E+05 1.18E+05
Feo 0.00344 0.00344 0.00344 0.00344
odnos 14.5 14.5 14.5 14.5
Fw 0.04988 0.04988 0.04988 0.04988
suma 3.043712 3.043712 3.0508843 3.0508843
B5 1.05462 0.8981744 1.05462 0.8981744
Fvk 0.05332 0.05332 0.0551131 0.0551131
pe 0.1548387 0.0717187 0.1548387 0.0717187
ps 0 0 0.0780824 0.0780824
ph 0 0 0.0780824 0.0780824
k1 0.0062953 0.002282 0.0062953 0.002282
B6 -4.4379 -4.4379 -4.0955274 -4.0955274
B1 -17.34 -17.34 -17.34 -17.34
B2 -14.466667 -15.676032 -14.466667 -15.676032
B3 34.358896 33.953372 34.358896 33.953372
B4 -0.1686906 -0.1686906 -0.132583 -0.132583
Kp 0.3679746 0.0913921 0.3679746 0.0913921
r1 9.748E-04 1.143E-05 9.748E-04 1.143E-05
X 0 0 0.5212406 0.5212406
ODE Report (RKF45)
Differential equations as entered by the user
[1] d(Fe)/d(V) = -r1
[2] d(Fs)/d(V) = r1
[3] d(Fh)/d(V) = r1
[4] d(T)/d(V) = (-deltaH1*r1)/suma
Explicit equations as entered by the user
[1] deltaH1 = 118000
[2] Feo = 0.00344
[3] odnos = 14.5
[4] Fw = Feo*odnos
[5] suma = (299*Fe)+(273*Fs)+(30*Fh)+(40.4*Fw)
[6] B5 = 1.302*(T^2)*(10^(-6))
[7] Fvk = Fe+Fs+Fh+Fw
[8] pe = 2.4*Fe/Fvk
[9] ps = 2.4*Fs/Fvk
[10] ph = 2.4*Fh/Fvk
[11] k1 = 1282.2*exp(-0.08539-(10925/T))
[12] B6 = -4.931*T*(10^(-3))
[13] B1 = -17.34
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