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HEMISKI Zbirka re{eni zada~i REAKTORI 3

HEMISKI Zbirka re{eni zada~i REAKTORI 3

HEMISKI Zbirka re{eni zada~i REAKTORI 3

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Zada~a 16<br />

^etvrti del. Idealen ceven <strong>re</strong>aktor (PFR)<br />

Serija CSTR–PFR i PFR–CSTR za ista izlezna konverzija<br />

I<strong>re</strong>verzibilna <strong>re</strong>akcija so kinetika od vtor <strong>re</strong>d, na pri-<br />

2<br />

mer ( rA) k C A , so konstanten vkupen broj molovi, t<strong>re</strong>ba da se<br />

izvede vo serija od eden CSTR i eden PFR. Reaktorite se so volum<strong>eni</strong><br />

so soodnos:<br />

a) VCSTR/VPFR = 10; b) VCSTR/VPFR = 1,0.<br />

Ako koncentracijata na A vo vleznata struja, CAo, e edini~na,<br />

da se poka`e koj <strong>re</strong>dosled na <strong>re</strong>aktorite }e bara pomal<br />

vkupen volumen, za dvata slu~aja, za postignuvawe na 90%<br />

konverzija na <strong>re</strong>aktantot.<br />

Re{<strong>eni</strong>e:<br />

Najnap<strong>re</strong>d vo brzinskiot izraz molskata koncentracija<br />

na <strong>re</strong>aktanot se zamenuva p<strong>re</strong>ku konverzija:<br />

2 2<br />

rA ) k C A k C Ao<br />

2<br />

( ( 1<br />

X ) k ( 1<br />

X ) . (1)<br />

Za sekoja serija na <strong>re</strong>aktorite }e se kombiniraat brzinskiot<br />

izraz (1) i ravenkata za dizajn na poedine~en <strong>re</strong>aktor.<br />

Zabele{ka: ravenkata za dizajn na PFR }e se <strong>re</strong>{ava so<br />

primena na tabli~en integral.<br />

a) VCSTR/VPFR = 10<br />

1) Serija PFR–CSTR<br />

V<br />

PFR<br />

V<br />

F<br />

k<br />

F<br />

Ao<br />

V<br />

F<br />

PFR<br />

Ao<br />

CSTR<br />

Ao<br />

<br />

X1<br />

X1<br />

<br />

( r<br />

) k(<br />

1<br />

0<br />

dX<br />

A<br />

0<br />

dX<br />

X )<br />

X1<br />

FAo<br />

X1<br />

VPFR<br />

<br />

(2)<br />

1<br />

X )<br />

k ( 1<br />

X )<br />

( 1<br />

1<br />

( X 2 X1)<br />

( X 2 X )<br />

<br />

<br />

k(<br />

r<br />

) k(<br />

1<br />

X<br />

A<br />

2<br />

2<br />

1<br />

2<br />

2 )<br />

2<br />

277

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