HEMISKI Zbirka re{eni zada~i REAKTORI 3

POLYMATH Results
Calculated values of the DEQ variables
[esti del. Industriski reaktori
Variable initial value minimal value maximal value final value
W 0 0 6600 6600
X 0 0 0.273805 0.273805
tetaI 0.2222 0.2222 0.2222 0.2222
To 565.55032 565.55032 565.55032 565.55032
CAo 72.33633 72.33633 72.33633 72.33633
T 565.55032 565.55032 798.53776 798.5377
K 2.7381906 0.7532669 2.7381906 0.7532669
k 5.266E-08 5.266E-08 1.949E-06 1.949E-06
R 2.756E-04 2.756E-04 0.0021888 0.0021888
FAo 20 20 20 20
Xeq 0.6233164 0.4646422 0.6233164 0.4646422
v 0.2764862 0.2764862 0.3903891 0.3903891
ODE Report (RKF45)
Differential equations as entered by the user
[1] d(X)/d(W) = R/FAo
Explicit equations as entered by the user
[1] tetaI = 0.2222
[2] To = (625+tetaI*298)/(1+tetaI)
[3] CAo = 5*(10^4)/To/(1+tetaI)
[4] T = To+(1040/(1+tetaI))*X
[5] K = 145.3*exp(-8.395*(T-298)/T)
[6] k = 0.0125*exp(-7000/T)
[7] R = k*(CAo^2)*((To/T)^2)*(((1-X)^2)-((X^2)/K))
[8] FAo = 20
[9] Xeq = (K^0.5)/(1+(K^0.5))
[10] v = (FAo/50000)*(1+tetaI)*T
Komentar za dobieniot rezultat: So dodavawe laden
vozduh na vlezot vo reaktorot se izbegnuva prethodno ladewe na
reaktantot vo toplinski razmenuva~ – edna operacija i eden ured
pomalku! Se poka`uva deka na vlezot vo reaktorot strujata na
reaktantot treba da se me{a so struja laden vozduh so protok
FI = FAo·0,2222 = 20·0,2222 = 4,444 mol/s. So ova razreduvawe vleznata
koncentracija na reaktantot se namaluva (72,336 mol/m 3 nasproti
94,835 mol/m 3 za ~ist reaktant so prethodno ladewe), {to
implicira namaluvawe na brzinata na reakcijata! No, od druga
strana, vleznata temperatura e povisoka (To = 565,55 K nasproti
To = 527,23 K), so {to pak se zgolemuva brzinata na reakcijata!
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