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HEMISKI Zbirka re{eni zada~i REAKTORI 3

HEMISKI Zbirka re{eni zada~i REAKTORI 3

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28<br />

Po~eten uslov za <strong>re</strong>{avawe na sistemot ravenki (86) e:<br />

t 0<br />

<br />

C<br />

C<br />

C<br />

A<br />

B<br />

C<br />

C<br />

C<br />

C<br />

Ai<br />

Bi<br />

Ci<br />

0<br />

0<br />

Ravenkata za dizajn na polu{ar`en <strong>re</strong>aktor p<strong>re</strong>ku<br />

stepenot na konverzija e samo edna dife<strong>re</strong>ncijalna ravenka:<br />

dX 1<br />

1<br />

( rA<br />

) V ( t)<br />

kC ACBV<br />

( t)<br />

. (87)<br />

dt nAo<br />

nAo<br />

Sè {to e pot<strong>re</strong>bno za kompletirawe na ravenkata (87) e da<br />

se sostavi stehiometriska tablica so ~ija pomo{ molskite koncentracii<br />

vo brzinskiot izraz }e se zamenat p<strong>re</strong>ku konverzija!<br />

Po~eten uslov za <strong>re</strong>{avawe na ravenkata (87) e: t = 0, X = 0.<br />

Ako <strong>re</strong>akcijata A B C<br />

se razgleduva kako <strong>re</strong>verzibilna,<br />

A + B C, ravenkite za dizajn }e bidat isti kako za i<strong>re</strong>verzibilna<br />

<strong>re</strong>akcija. Razli~en e samo brzinskiot izraz,<br />

( rA) ( rB<br />

) rC<br />

k1C<br />

ACB<br />

k2CC<br />

.<br />

So primena na uslovot za ramnote`a i na stehiometriska<br />

tablica za polu{ar`en <strong>re</strong>aktor, se dobiva ravenka za v<strong>re</strong>menskata<br />

promena na ramnote`nata konverzija:<br />

( rA<br />

) 0 <br />

nAo<br />

X<br />

*<br />

k1<br />

CC<br />

V ( t)<br />

K <br />

.<br />

k * *<br />

*<br />

*<br />

2 C ACB<br />

nAo<br />

( 1<br />

X ) [( nBi<br />

FBot)<br />

nAo<br />

X ]<br />

V ( t)<br />

V ( t)<br />

Zemaj}i deka n Bi<br />

venkata se dobiva:<br />

0 , a V ( t)<br />

V ot<br />

, so s<strong>re</strong>duvawe na ra-<br />

*<br />

X ( V<br />

K <br />

*<br />

( 1<br />

X )( F<br />

o<br />

Bo<br />

o <br />

<br />

t)<br />

o<br />

t n<br />

Ao<br />

X<br />

*<br />

*<br />

. (88)<br />

)

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