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HEMISKI Zbirka re{eni zada~i REAKTORI 3

HEMISKI Zbirka re{eni zada~i REAKTORI 3

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Petti del. Kataliti~ki <strong>re</strong>aktor so fiksen sloj katalizator (PBR)<br />

vite na vlezot vo <strong>re</strong>aktorot se: To = 625 o C, Po = 1,2 atm. i molski<br />

protok na <strong>re</strong>aktantot FEo = 6,12 kmol/h. Brzinata na <strong>re</strong>akcijata<br />

e slednava zavisnost od temperaturata i parcijalnite pritisoci<br />

na u~esnicite vo <strong>re</strong>akcijata:<br />

1<br />

( rE<br />

) k ( pE<br />

pS<br />

pH<br />

) kmol/(kgkath);<br />

pi<br />

K<br />

k exp(<br />

9,<br />

43 ( 10971/<br />

T ))<br />

h) ; T<br />

K exp(<br />

15,<br />

32 <br />

( 14643/<br />

T<br />

; kmol/(atmkg<br />

)) ( atm).<br />

kat<br />

( atm);<br />

( K);<br />

Toplinata na <strong>re</strong>akcijata i specifi~nite toplini mo`at<br />

da se zemat kako s<strong>re</strong>dni (konstantni) so slednive v<strong>re</strong>dnosti:<br />

H<br />

~<br />

CP<br />

~<br />

C<br />

r<br />

, E<br />

P,<br />

H<br />

139000 kJ/kmolE<br />

;<br />

~<br />

299 kJ/(kmolE<br />

K) ; C<br />

~<br />

30kJ/(kmol<br />

K) ; C<br />

H<br />

P,<br />

S<br />

P,<br />

W<br />

273kJ/(kmol<br />

K) ;<br />

40kJ/(kmol<br />

W<br />

S<br />

K) .<br />

Da se p<strong>re</strong>smeta pot<strong>re</strong>bnata koli~ina katalizator za 45%<br />

konverzija na etilbenzenot so adijabatska rabota na <strong>re</strong>aktorot.<br />

Re{<strong>eni</strong>e:<br />

Stanuva zbor za adijabatski PBR i za <strong>re</strong>akcija vo parna<br />

faza so promenliv vkupen broj molovi. Za da se odgovori na postavenoto<br />

pra{awe vo ovaa zada~a, pot<strong>re</strong>bni se: molskiot bilans<br />

(ravenkata za dizajn), toplinskiot bilans, brzinskiot izraz i<br />

stehiometrijata (za p<strong>re</strong>smetki p<strong>re</strong>ku konverzija na <strong>re</strong>aktantot).<br />

Najnap<strong>re</strong>d da sostavime stehiometriska tablica:<br />

F ( X )<br />

Fio Fi() Fi(X)<br />

i pi<br />

( X ) P<br />

FT<br />

( X )<br />

E FEo<br />

FEo FEo(1–X) pE <br />

( 1<br />

X )<br />

P<br />

(=FEoX)<br />

( 21<br />

X )<br />

X<br />

S 0 FEoX pS P<br />

( 21<br />

X )<br />

X<br />

H 0 FEoX pH P<br />

( 21<br />

X )<br />

W FW=FEoW=20FEo 20FEo 20FEo<br />

FTo FT(X)=FEo(21+X)<br />

323

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