HEMISKI Zbirka re{eni zada~i REAKTORI 3

356
dT
dV
( H
r )( r
C
A
)
smesa P,
smesa
. (111)
Ravenkata (111), primeneta za uslovite vo ovaa zada~a, }e
izgleda vaka:
dT
dW
( H
C
smesa
r
)
P,
smesa
F
Ao
dX
dW
smesa
( FAoM
A)
( F W MW
) FAo
( M A 30M
W)
20,
0325(
106 30 18)
12941kg/h
;
140000
( T To
) 20,
0325X
;
12941
0,
7
T To
309, 6 X 923 309,
6 X .
(5)
]e izbereme da ja re{avame ravenkata (4)! Vo kombinacija
so toplinskiot bilans (5) i so primena na solverot za
diferencijalni ravenki od POLYMATH se dobivaat slednive
rezultati:
POLYMATH Results
Calculated values of the DEQ variables
Variable initial value minimal value maximal value final value
W 0 0 5500 5500
X 0 0 0.4005093 0.4005093
FAo 20.0325 20.0325 20.0325 20.0325
T 923 799.00231 923 799.00231
k 0.1881447 0.0296809 0.1881447 0.0296809
K 0.6571373 0.0387762 0.6571373 0.0387762
R 0.0060692 4.421E-04 0.0060692 4.421E-04
ODE Report (RKF45)
Differential equations as entered by the user
[1] d(X)/d(W) = R/FAo
Explicit equations as entered by the user
[1] FAo = 20.0325
[2] T = 923-309.6*X
[3] k = 2.2*(10^(4.1-4770/T))
[4] K = 0.23*exp(-(16832/T)+19.286)
[5] R = k*(((1-X)/(31+X))-((X^2)/K/((31+X)^2)))
;