HEMISKI Zbirka re{eni zada~i REAKTORI 3

[5] k1 = 1.79*(10^4)*exp(-20800/1.9872/T)
[6] R = (k1*25132*A)-(k2*0.01138*B)
[7] Cpi = 30
[8] Fa = Fao*(1-X)
[9] Fb = 3*Fao*(1-X)
[10] Fc = Fao*(0.174+2*X)
[11] Fi = 87
[12] Ua = 21000
[13] Cpcf = 28.033+0.0264*Tf
[14] Fbo = 3*Fao
[15] Ft = Fao*(4.348-2*X)
[16] yC = Fc/Ft
[17] Cpa = 28.425+0.00376*T
[18] Cpb = 27.196+0.004184*T
[19] Cpc = 28.033+0.0264*T
[20] suma = Fa*Cpa+Fb*Cpb+Fc*Cpc+Fi*Cpi
[21] Cpaf = 28.425+0.00376*Tf
[22] Cpbf = 27.196+0.004184*Tf
[23] deltaH = 77743+(54*T)-(0.01825*(T^2))
[24] Fco = 87
[25] C = Fao*Cpaf+Fbo*Cpbf+Fco*Cpcf+Fi*Cpi
[26] yA = Fa/Ft
[27] yB = Fb/Ft
[28] P = 286
[29] pA = yA*P
[30] pB = yB*P
[31] pC = yC*P
Stepen na konverzija na azot
598
X
0.4
0.32
0.24
0.16
0.08
0
To=694 K
Promena na stepenot na konverzija, X(V)
To=674 K
0 1 2 3 4 5
Volumen na katalizator (m3)
V (m 3 )
Grafik 4. Promena na konverzijata, X(V)