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HEMISKI Zbirka re{eni zada~i REAKTORI 3

HEMISKI Zbirka re{eni zada~i REAKTORI 3

HEMISKI Zbirka re{eni zada~i REAKTORI 3

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Petti del. Kataliti~ki <strong>re</strong>aktor so fiksen sloj katalizator (PBR)<br />

nata numeri~ka v<strong>re</strong>dnost. Potoa izrazot se s<strong>re</strong>duva i se dobiva<br />

sledniov gotov izraz koj }e se prim<strong>eni</strong> za p<strong>re</strong>smetka na izotermna<br />

rabota na <strong>re</strong>aktorot na 275 o C:<br />

( r<br />

A<br />

) <br />

( 1<br />

<br />

<br />

1,<br />

876<br />

p<br />

<br />

0,<br />

4304 p<br />

A<br />

A<br />

pB<br />

pC<br />

<br />

<br />

0,<br />

589 <br />

2,<br />

895 p<br />

<br />

2 2<br />

( 1 ) 3<br />

3 <br />

1,<br />

876<br />

X X <br />

<br />

<br />

( 1,<br />

155 )<br />

2<br />

0,<br />

589(<br />

1,<br />

155 )<br />

<br />

X<br />

X<br />

<br />

<br />

;<br />

2<br />

( 1<br />

X ) 3<br />

X 3<br />

<br />

1<br />

0,<br />

4304 2,<br />

895<br />

( 1,<br />

155 ) ( 1,<br />

155 )<br />

<br />

<br />

X<br />

X <br />

( 5,<br />

628<br />

0,<br />

8727<br />

X 35,<br />

165 X )<br />

( rA ) <br />

. (2)<br />

2<br />

( 2,<br />

446 8.<br />

394 X )<br />

Se kombiniraat ravenkata (1) i izrazot (2) otkako p<strong>re</strong>thodno<br />

e p<strong>re</strong>smetan vlezniot molski protok na <strong>re</strong>aktantot A (po<br />

edna cevka):<br />

F<br />

Ao<br />

F<br />

Ao FTo<br />

W<br />

F<br />

Ao<br />

/ 1,<br />

155 4,<br />

2 / 1,<br />

155 <br />

2<br />

B<br />

)<br />

2<br />

2<br />

3,<br />

6363 kmol/h ,<br />

0,<br />

4<br />

L 0.<br />

785 D sloj<br />

dX<br />

;<br />

F<br />

( r<br />

)<br />

Ao<br />

3,<br />

6363kmol/h<br />

; D 0,<br />

05 m;<br />

<br />

0,<br />

4<br />

0<br />

sloj<br />

A<br />

1500 kg/m<br />

( 2,<br />

446 8,<br />

394 X )<br />

0,<br />

80953 L <br />

dX ( ) .<br />

2 f X dX (3)<br />

( 5,<br />

628 0,<br />

8727 X 35,<br />

165 X )<br />

0<br />

So ravenkata (3) se p<strong>re</strong>smetuva dol`inata na edna cevka,<br />

koja e i dol`ina na sekoja cevka vo peve}ecevniot <strong>re</strong>aktor.<br />

Kolku cevki }e go so~inuvaat <strong>re</strong>aktorot ne }e mo`eme da p<strong>re</strong>smetame,<br />

bidej}i ne e poznat kapacitetot na <strong>re</strong>aktorot!<br />

Kako }e ja op<strong>re</strong>delime v<strong>re</strong>dnosta na integralot vo ravenkata<br />

(3) e pra{awe na izbor koj, od svoja strana, zavisi od promenata<br />

na <strong>re</strong>cipro~nata v<strong>re</strong>dnost na brzinata na <strong>re</strong>akcija so<br />

konverzijata. Taa zavisnost p<strong>re</strong>tstavena grafi~ki izgleda vaka:<br />

2<br />

0,<br />

4<br />

0<br />

3<br />

;<br />

335

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