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HEMISKI Zbirka re{eni zada~i REAKTORI 3

HEMISKI Zbirka re{eni zada~i REAKTORI 3

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Petti del. Kataliti~ki <strong>re</strong>aktor so fiksen sloj katalizator (PBR)<br />

Brzinskiot izraz p<strong>re</strong>ku konverzija se dobiva so zamena na<br />

izrazite za parcijalnite pritisoci od stehiometriskata tablica:<br />

<br />

2<br />

p<br />

<br />

B pH<br />

<br />

<br />

( 1<br />

X ) X<br />

( r<br />

<br />

<br />

<br />

A ) k(<br />

T ) p A<br />

k<br />

. (1)<br />

K <br />

<br />

<br />

( 31<br />

X )<br />

2<br />

K(<br />

31<br />

X ) <br />

Temperaturnata zavisnost na brzinskata konstanta e poznata,<br />

a za kompletirawe na brzinskiot izraz pot<strong>re</strong>bno e da se<br />

izvede K(T). Soglasno so Van’t Hoff-ovata ravenka,<br />

K<br />

ln<br />

K<br />

T2<br />

T1<br />

H<br />

<br />

R<br />

se dobiva sledniov izraz za K(T):<br />

o r<br />

<br />

1 1 <br />

<br />

, (14)<br />

T2<br />

T1<br />

<br />

o<br />

( H<br />

) 1 1 <br />

r <br />

K(<br />

T ) K(<br />

873)<br />

exp<br />

,<br />

<br />

R T 873 <br />

(2)<br />

5<br />

1,<br />

4 10<br />

1 1 <br />

16873 <br />

K(<br />

T ) 0,<br />

23exp<br />

<br />

0,<br />

23exp<br />

19,<br />

286.<br />

<br />

8,<br />

315 T 873 <br />

T <br />

Ravenkata za dizajn na ceven kataliti~ki <strong>re</strong>aktor vo integralna<br />

forma za razgleduvanata kinetika e:<br />

W<br />

F<br />

Ao<br />

<br />

X<br />

dX<br />

( r<br />

)<br />

<br />

0<br />

A<br />

0,<br />

4<br />

0<br />

dX<br />

<br />

2<br />

<br />

( 1 X ) X<br />

k(<br />

T ) <br />

<br />

( 31 X ) K(<br />

T )( 31 X )<br />

2<br />

. (3)<br />

<br />

<br />

<br />

<br />

Ravenkata (3) se <strong>re</strong>{ava so numeri~ka integracija, na primer<br />

so Simpson-ovoto 1/3 pravilo. Ako se koristi nekoj softver,<br />

toga{ ravenkata za dizajn se primenuva vo nejziniot dife<strong>re</strong>ncijalen<br />

oblik:<br />

dX<br />

dW<br />

( r<br />

<br />

F<br />

A<br />

Ao<br />

)<br />

; ( r<br />

A<br />

<br />

2<br />

( 1 )<br />

) ( ) <br />

X X<br />

k T <br />

<br />

( 31<br />

X ) K(<br />

T)(<br />

31<br />

X )<br />

Vo sekoj slu~aj }e bide pot<strong>re</strong>ben i toplinskiot bilans.<br />

Soglasno so zadad<strong>eni</strong>te podatoci ravenkata na toplinskiot bilans<br />

za adijabatska rabota na <strong>re</strong>aktorot e ravenkata (111)<br />

2<br />

<br />

.<br />

<br />

<br />

(4)<br />

355

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