HEMISKI Zbirka re{eni zada~i REAKTORI 3

Petti del. Kataliti~ki reaktor so fiksen sloj katalizator (PBR)
Kone~nata forma na brzinskiot izraz kako funkcija od
konverzijata i temperaturata (preku brzinskata i ramnote`nata
konstanta i K–konstantite) e:
A
B
C
I
0,
5
X ( 1 0,
035X
)
k ( 1 X )( 1,
57 0,
5X
)
1
0,
5
K ( 1 X )( 1,
57 0,
5X
)
( rA)
. (1)
2
22,
414
14, 28(
1
0,
035X
) K ( 1
X ) K X
A + 0,5B C ; A = 1; B = 11/7 = 1,57; I = 82/7 = 11,71
Fio Fi() Fi(X) pi(X)
FAo
FBo = FAoB
= 1,57FAo
0
FI = FAoI
= 11,71FAo
FTo =14,28 FAo
FA = FAo–
= FAoX
FB =
= FBo – 0,5
1
FA = FAo(1–X)
FB=
=FAo(1,57–0,5X)
FC = FC = FAoX
11,71FAo 11,71 FAo
FT =
14,28FAo – 0,5FAoX
= FTo – 0,5FAoX =
14,28FAo(1–0,035X)
p
p
p
p
p
p
A
A
B
B
C
C
2
FA(
X )
yAP
1
F ( X )
( 1
X )
14,
28(
1
0,
035X
)
T
FB
( X )
yBP
1
F ( X )
( 1,
57 0,
5X
)
14,
28(
1
0,
035X
)
14,
28
( 1
T
FC
( X )
yCP
1
F ( X )
T
X
0,
035X
)
Izrazot (1) se kombinira so ravenkata za dizajn na PBR:
W
F
Ao
0,
6
0
0,
6
dX
1
( , ) ; ( , ) .
( ) f R X T dX f R X T
r
( r
)
A
0
Ravenkata (2) e podgotvena za numeri~ka integracija i se
re{ava zaedno so toplinskiot bilans:
T To 211 X 688
211
X . (3)
A
(2)
327