HEMISKI Zbirka re{eni zada~i REAKTORI 3

More documents

Recommendations

Info

[esti del. Industriski reaktori Stehiometriska tablica: U~esnik vo reakcija io C6H6 (B) Bo n n , , ) n n , n , n ) i ( 1 2 3 n n B nBo 1 C6H5Cl (M) 0 M 1 2 C6H4Cl2 (D) 0 D 2 3 C6H3Cl3 (T) 0 T 3 Cl2 (C) t F Co n C F n B n Bo i ( M D T n M n n D Co n T n t HCl (A) 0 n A 1 2 3 1 2 3 n C F Co ( nM nD nT n t ( nM 2nD 3nT ) nT ; 2 nD 3 nD nT ; 1 nM 2 nM nD n 3 T Molskite koncentracii na benzenot i hlorot, soglasno so stehiometriskata tablica, se slednite: nB CB CBo ( CM CD CT ) (13) V nC FCot CC ( CM 2CD 3CT ) (14) V V Molskite koncentracii na benzenot i hlorot se izrazeni preku molskite koncentracii na produktite na hloriraweto! Spored toa, izrazite (13) i (14) moàt da se upotrebat kako algebarski ravenki namesto nivnite diferencijalni ravenki na molskite bilansi, na koj na~in bi se re{aval sistem od tri diferencijalni i dve algebarski ravenki namesto sistemot (12). Rezultatot e ist! Kone~no }e go izbereme solverot za diferencijalni ravenki od POLYMATH, za ~ija primena se sostavuva programata {to e dadena podolu so izve{tajot so rezultatite. Kako }e se vidi, vo programata se vneseni i: izrazot za potro{uva~ka na hlor vo odnos na eden mol benzen dodaden na po~etokot (Y); iz- . ) 483
azot za vkupno sozdadena kiselina (nA); izrazot za vkupno dodadena koli~ina hlor (nC = FCo t); izrazot za koli~ina benzen vo sekoe vreme (nB); izrazot za stepenot na konverzija na benzenot (XB); izrazite za raspredelba na produktite (SMD, SMT, SDT). Rezultatite dobieni za vreme na reakcija t = 5990 s, koga e postignat maksimum na krivata CM(t), se slednive: POLYMATH Results Calculated values of the DEQ variables Variable initial value minimal value maximal value final value t 0 0 5990 5990 Cb 11.28 1.1554609 11.28 1.1554609 Cm 0 0 8.3757905 8.3757905 Cd 0 0 1.7421522 1.7421522 Ct 0 0 0.0065964 0.0065964 Cc 0 0 0.100116 0.100116 k1 0.00884 0.00884 0.00884 0.00884 k2 0.001105 0.001105 0.001105 0.001105 k3 3.683E-05 3.683E-05 3.683E-05 3.683E-05 Fco 0.01 0.01 0.01 0.01 nc 0 0 59.9 59.9 V 5 5 5 5 nb 56.4 5.7773047 56.4 5.7773047 A 11.28 2.2096937 11.28 2.2096937 na 0 0 59.39942 59.39942 Y 0 0 1.0531812 1.0531812 Xb 0 0 0.8975655 0.8975655 SMD 0 0 811.73309 4.8077258 SMT 0 0 2.716E+06 1269.7362 SDT 0 0 7999.9884 264.10327 ODE Report (RKF45) Differential equations as entered by the user [1] d(Cb)/d(t) = -k1*Cb*Cc [2] d(Cm)/d(t) = k1*Cb*Cc-k2*Cm*Cc [3] d(Cd)/d(t) = k2*Cm*Cc-k3*Cd*Cc [4] d(Ct)/d(t) = k3*Cd*Cc [5] d(Cc)/d(t) = (Fco/V)-(k1*Cc*A) Explicit equations as entered by the user [1] k1 = 0.00884 [2] k2 = 0.00884/8 [3] k3 = 0.00884/8/30 484
Page 1 and 2:
HEMISKI REAKTORI 3 Zbirka re{eni za
Page 3 and 4:
Skopje, 2010
Page 6 and 7:
Predgovor . . . Hemiskiot reaktor e
Page 8 and 9:
lot da se stekne so ve{tina da gi k
Page 10:
~ite }e mu ovozmoì preku niv da go
Page 13 and 14:
5. TOPLINSKI BILANSI ..............
Page 15 and 16:
XIV êtvrti del IDEALEN CEVEN REAKT
Page 17 and 18:
Zada~a 4. Adijabatski PBR so pretho
Page 20 and 21:
1. STEHIOMETRIJA 1.1. Prost reakcio
Page 22 and 23:
Prv del. Definicii, koncepti, stehi
Page 24 and 25:
2. TOPLINA NA REAKCIJA I HEMISKA RA
Page 26 and 27:
Page 28 and 29:
3. IZRAZI ZA BRZINA NA REAKCIJA 3.1
Page 30 and 31:
Page 32:
Page 35 and 36:
Molskite koncentracii vklu~eni vo b
Page 37 and 38:
kako ravenkata (52). Razlikata e vo
Page 39 and 40:
Ravenkite za dizajn na cevniot reak
Page 41 and 42:
Ravenkata za dizajn na ceven reakto
Page 43 and 44:
Za presmetka na brojot na reaktorit
Page 45 and 46:
28 Po~eten uslov za re{avawe na sis
Page 47 and 48:
Toplinski bilansi za adijabatska ra
Page 49 and 50:
32 T H ( r ) V r A a, vlez Ta, vle
Page 51 and 52:
Toplinski bilansi za izotermna rabo
Page 53 and 54:
Osnovnata ravenka na toplinskiot bi
Page 55 and 56:
38 H / L Q q dz Ua ( T T ) dz ;
Page 58 and 59:
Page 60 and 61:
Page 62 and 63:
Page 64 and 65:
Page 66 and 67:
Page 68 and 69:
Page 70:
Vtor del [arèn reaktor
Page 73 and 74:
Re{enie: a) Za izotermna rabota na
Page 75 and 76:
POLYMATH Results Calculated values
Page 77 and 78:
Explicit equations as entered by th
Page 79 and 80:
Jasno e deka vremeto potrebno za re
Page 81 and 82:
Zada~a 2 64 [arèn reaktor i CSTR s
Page 83 and 84:
Rezultatot e deka so eden {arèn re
Page 85 and 86:
Vo ravenkata za dizajn (48) gi zame
Page 87 and 88:
a) Brojot na {arìte koj }e go obez
Page 89 and 90:
Kone~nata forma na brzinskiot izraz
Page 91 and 92:
Page 93 and 94:
76 Mi % (w/w) 1 3 Cio smesa kmol/m
Page 95 and 96:
Re{enie: Samo so primena na ravenka
Page 97 and 98:
data e so sè pomali temperaturni r
Page 99 and 100:
Page 101 and 102:
) Za varijantata na razmena na topl
Page 103 and 104:
( H r )( rA ) V TW , vlez T
Page 105 and 106:
Vkupnata koli~ina toplina {to }e se
Page 107 and 108:
) Za presmetka na vremeto na reakci
Page 109 and 110:
( 1 X ) To C A C Ao ; (1) ( 1 0, 5
Page 111 and 112:
11620 X T To . (6) 38, 73 12, 91X
Page 113 and 114:
96 t r t r C P dP dP C Ao ; 0, 5(
Page 115 and 116:
a) Od kineti~kite podatoci da se op
Page 117 and 118:
100 C C W n C Wo / V Wo W rastvor
Page 119 and 120:
A B ; ( rA) k1C A k2C B ; 7 1 k
Page 121 and 122:
) Vremeto na reakcija za 80% konver
Page 123 and 124:
presmetki za izotermna rabota na re
Page 126 and 127:
Zada~a 1 Hidrogenacija na etilen vo
Page 128 and 129:
Tret del. Proto~en reaktor od rezer
Page 130 and 131:
Page 132 and 133:
Page 134 and 135:
1 Tret del. Proto~en reaktor od rez
Page 136 and 137:
POLYMATH Results Tret del. Proto~en
Page 138 and 139:
Page 140 and 141:
Page 142 and 143:
Page 144 and 145:
Page 146 and 147:
Page 148 and 149:
Page 150 and 151:
Page 152 and 153:
Page 154 and 155:
Page 156 and 157:
Page 158 and 159:
Page 160 and 161:
F F X X A1 B1 1 1 Tret del. Proto~e
Page 162 and 163:
C B2 0, 1056 F F X 2 A2 B2 2 Tre
Page 164 and 165:
Page 166 and 167:
Page 168 and 169:
Zada~a 8 Tret del. Proto~en reaktor
Page 170 and 171:
Explicit equations [1] R = 0 [2] T
Page 172 and 173:
Page 174 and 175:
X * XMB XEB X*; XMB; XEB 1 0.8 0.6
Page 176 and 177:
Page 178 and 179:
XMB XEB 1 0.8 0.6 0.4 0.2 Zada~a 10
Page 180 and 181:
Page 182 and 183:
( C C A1 ( C C A2 ( C C A3 A Tret d
Page 184 and 185:
Page 186 and 187:
Page 188 and 189:
Page 190 and 191:
Page 192 and 193:
Page 194 and 195:
Page 196 and 197:
Page 198 and 199:
Page 200 and 201:
Page 202 and 203:
Page 204 and 205:
Page 206 and 207:
1 Tret del. Proto~en reaktor od rez
Page 208 and 209:
Page 210 and 211:
Zada~a 15 Tret del. Proto~en reakto
Page 212 and 213:
C C C C Bo Bo Wo Wo Tret del. Proto
Page 214 and 215:
Page 216 and 217:
Page 218 and 219:
dT dt Tret del. Proto~en reaktor od
Page 220:
Page 224 and 225:
Zada~a 1 Endotermna reakcija vo gas
Page 226 and 227:
êtvrti del. Idealen ceven reaktor
Page 228 and 229:
Page 230 and 231:
Re{enie: êtvrti del. Idealen ceven
Page 232 and 233:
Page 234 and 235:
Page 236 and 237:
A (NO) B (O2) C (NO2) I (N2) êtvrt
Page 238 and 239:
Page 240 and 241:
Page 242 and 243:
Page 244 and 245:
Page 246 and 247:
Page 248 and 249:
Page 250 and 251:
Page 252 and 253:
Page 254 and 255:
Page 256 and 257:
X 0 0, 2 êtvrti del. Idealen ceve
Page 258 and 259:
Page 260 and 261:
Page 262 and 263:
Page 264 and 265:
Page 266 and 267:
Page 268 and 269:
Page 270 and 271:
Page 272 and 273:
Page 274 and 275:
Page 276 and 277:
Re{enie: a) Izotermna rabota: êtvr
Page 278 and 279:
Page 280 and 281:
Page 282 and 283:
Page 284 and 285:
T (K) k (T) izraz (4) êtvrti del.
Page 286 and 287:
Page 288 and 289:
( r êtvrti del. Idealen ceven reak
Page 290 and 291:
0,22 êtvrti del. Idealen ceven rea
Page 292 and 293:
Page 294 and 295:
Zada~a 16 êtvrti del. Idealen ceve
Page 296 and 297:
V PFR k F Ao êtvrti del. Idealen c
Page 298 and 299:
Page 300 and 301:
Page 302 and 303:
Page 304 and 305:
Page 306 and 307:
Page 308 and 309:
Page 310 and 311:
Page 312 and 313:
Page 314 and 315:
Page 316 and 317:
Page 318 and 319:
Page 320 and 321:
Page 322 and 323:
Page 324 and 325:
Page 326 and 327:
Page 328 and 329:
Page 330 and 331:
Ropt=1,5 Vmin=1884litri êtvrti del
Page 332:
Petti del Kataliti~ki reaktor so fi
Page 335 and 336:
ili 318 - diferencijalen oblik, kak
Page 337 and 338:
Od izve{tajot i od rezultatite od p
Page 339 and 340:
Grafi~ka prezentacija na site rezul
Page 341 and 342:
Ponatamu podgotvuvame brzinski izra
Page 343 and 344:
Zada~a 3 326 Reakcija vo gasna faza
Page 345 and 346:
Iako brzinskiot izraz e prili~no go
Page 347 and 348:
330 Fio Fi() Fi(X) pi = yiP = (Fi/F
Page 349 and 350:
332 A FAo B Bo Fio Fi() Fi(X) F 2F
Page 351 and 352:
Ako reakcijata se odviva vo pove}ec
Page 353 and 354:
Isto taka, dobro e da znaeme kolku
Page 355 and 356:
Prvo, brzinskiot izraz se pi{uva vo
Page 357 and 358:
340 Yexp X Ycalc 6087E-12 0.105 8.0
Page 359 and 360:
Re{enie: Rabota so razmena na topli
Page 361 and 362:
344 dT dV dT dT dT FT CP 65, 9 6,
Page 363 and 364:
Kako {to moè da se vidi od dobieni
Page 365 and 366:
Komentari: 1) So adijabatska rabota
Page 367 and 368:
za KC(T) se dobiva sledniov izraz:
Page 369 and 370:
352 W (kg) W (kg) (-rA) = f(W) W (k
Page 371 and 372:
354 - toplina na reakcijata: Hr = 1
Page 373 and 374:
356 dT dV ( H r )( r C A ) smes
Page 375 and 376:
358 Potrebniot broj reaktorski cevk
Page 377 and 378:
360 C TS r a, T kT pT Cv K
Page 379 and 380:
Page 381 and 382:
364 Za brzinski izraz preku konverz
Page 383 and 384:
366 0, 2 0 h f ( X ) dX 3 0, 2 0
Page 385 and 386:
368 Sega go pi{uvame bilansot na ak
Page 387 and 388:
Re{avawe na ravenkata (8) zna~i pre
Page 389 and 390:
Analizata za razli~ni vrednosti na
Page 391 and 392:
Re{enie: 1) Ravenkata za dizajn na
Page 393 and 394:
[8] Po = (1-X)*P/(2-X) [9] Ph = (1-
Page 395 and 396:
1 ( rO ) f ( W ) ili D f ( X )
Page 397 and 398:
380 f 9, 375 ( 1, 75 0, 0585 ?) 9
Page 399 and 400:
Za da zaklu~ime dali ovoj volumen e
Page 401 and 402:
pritisokot i konverzijata. Zavisnos
Page 403 and 404:
k 3.194E-05 3.194E-05 3.194E-05 3.1
Page 406:
[esti del Industriski reaktori
Page 409 and 410:
392 - vlez vo reaktorot: T C o 650
Page 411 and 412:
Izleznata konverzija normalno raste
Page 413 and 414:
gramata se vnesuvaat ovie dve raven
Page 415 and 416:
Toplinskiot bilans vo ovoj slu~aj }
Page 417 and 418:
400 X 0.5 0.4 0.3 0.2 0.1 1 2 3 4 5
Page 419 and 420:
402 1060 1032 T(K) X 1004 976 948 9
Page 421 and 422:
Zada~a 2 404 Piroliza na etan do et
Page 423 and 424:
406 C A C Ao ( 1 X ) ; ( 1 0, 6X )
Page 425 and 426:
408 X 1 0.8 0.6 0.4 0.2 0 900 950 1
Page 427 and 428:
T 1053 930.72495 1053 930.72495 FAo
Page 429 and 430:
sokot, potoa podatokot za konstante
Page 431 and 432:
Za vrednosti na Re-brojot pome|u 30
Page 433 and 434:
416 V (m 3 ) P(V) V (m 3 ) X(T) T (
Page 435 and 436:
eaktorot: dali toa }e bide izotermn
Page 437 and 438:
2) Da se povtori re{enieto pod 1),
Page 439 and 440:
e{avawe na zada~ata da se koristi p
Page 441 and 442:
ni ravenki, (5), (6) i (7), zavisno
Page 443 and 444:
Ramnoteà: Za da se kompletira slik
Page 445 and 446:
Explicit equations [1] Feo = 0.0034
Page 447 and 448:
Page 449 and 450: 432 T (K) Presek na ramnote`na i ad
Page 451 and 452: cionen mehanizam koj, pokraj glavna
Page 453 and 454: 436 - vodorod, H: - benzen, B: - et
Page 455 and 456: Za da se re{i sistemot od 7+1 difer
Page 457 and 458: 440 FE(V) Promena na molskite proto
Page 459 and 460: 442 F F F F F F F E FEo 1) 1 ( 1
Page 461 and 462: enzen izvedena pod dadenite uslovi
Page 463 and 464: - toplinski kapaciteti na reaktanto
Page 465 and 466: dX (rA ) . (3) dW FAo Ravenkata (3
Page 467 and 468: FAo 20 20 20 20 T 527.23 527.23 812
Page 469 and 470: 2) Novata varijanta na adijabatskat
Page 471 and 472: 454 C P, A F C i H r C P, i P, B
Page 473 and 474: Zna~i, so ovaa varijanta razreduvaw
Page 475 and 476: segment }e treba da se presmetuva p
Page 477 and 478: dodeka izrazite za molskite koncent
Page 479 and 480: Explicit equations as entered by th
Page 481 and 482: Toi 650.66442 650.66442 650.66442 6
Page 483 and 484: Sedmiot segment: POLYMATH Results C
Page 485 and 486: Explicit equations as entered by th
Page 487 and 488: 470 X 0.4 0.32 0.24 0.16 0.08 0 500
Page 489 and 490: Zada~a 5 472 Proizvodstvo na glukon
Page 491 and 492: 30 24 / 144 5 . Zna~i, na po~etok
Page 493 and 494: T a b e l a 1 Po~etok na ciklus 10
Page 495 and 496: 478 Vmax / K m 1 5 3 k 0, 016 h
Page 497 and 498: te~nata reakciona smesa se odrùva
Page 499: 482 r r , r , 1 r , 2 r , 3 C
Page 503 and 504: 486 CB(t) CM(t) t (s) t (s) t (s) A
Page 505 and 506: Zada~a 7 488 Kataliti~ka oksidacija
Page 507 and 508: 490 dX dW ( rA ) F1 ( X , T ) (2)
Page 509 and 510: Podolu se izve{taite i grafi~kite p
Page 511 and 512: K2 13.126279 5.2903007 13.126279 5.
Page 513 and 514: Reakcioniot plan pretstavuva grafik
Page 515 and 516: 498 Podatoci potrebni za re{avawe n
Page 517 and 518: nosno ravenka za dizajn (preku konv
Page 519 and 520: 0, 01094 kmol ( rA ) k 0, 425 P ; P
Page 521 and 522: - proizvod od koeficientot na preno
Page 523 and 524: 506 - Drugite podatoci se: sloj 5
Page 525 and 526: 508 X(W) W (kg) Zavisnost konverzij
Page 527 and 528: temperatura dava podobar efekt i vo
Page 529 and 530: Bidej}i reakcijata e egzotermna so
Page 531 and 532: 514 - Kinetika r ( r k r k 1 1 2 2
Page 533 and 534: 516 k k r k k 1 1 1 2 2 2 dF C dV d
Page 535 and 536: So solverot za diferencijalni raven
Page 537 and 538: na koncentracijata na kislorodot. T
Page 539 and 540: 522 Varijanta 2. Proces so kislorod
Page 541 and 542: Ravenka za dizajn na PBR: Ravenkata
Page 543 and 544: Sistemot diferencijalni ravenki (11
Page 545 and 546: 528 FA(W) FB(W) FC(W) W (kg) FD(W);
Page 547 and 548: POLYMATH Results Calculated values
Page 549 and 550: Ravenkite {to treba da se kombinira
Page 551 and 552:
vo 7648.55 7648.55 7648.55 7648.55
Page 553 and 554:
536 r2(W) r1(W) Grafik na zavisnost
Page 555 and 556:
Y = 1 7, 077 ( 1 0, 45) ( 1 0, 4
Page 557 and 558:
540 r2(W) r1(W) W (kg) Grafik na za
Page 559 and 560:
1 ( rA ) 1 r1 k1 p A pB kmol/(kg
Page 561 and 562:
544 Za specifi~nata povr{ina se zam
Page 563 and 564:
na toplina i za protokot na vodata
Page 565 and 566:
Cpa 44.257982 44.257982 65.187219 5
Page 567 and 568:
Na prviot grafik ne e pretstavena z
Page 569 and 570:
552 Da se presmetaat i analiziraat
Page 571 and 572:
FMo 9, 07 3 CMo 0, 169 kmol/m .
Page 573 and 574:
povtorno treba da se re{at ravenkat
Page 575 and 576:
da se odviva taka vleznata temperat
Page 577 and 578:
560 ~ , i iC P 35 12, 518 0, 05
Page 579 and 580:
Vremeto na nestacionarniot period n
Page 581 and 582:
564 C C C Ao Bo Mo F F Ao o Bo
Page 583 and 584:
Kako {to se gleda od dobienite rezu
Page 585 and 586:
Zada~a 11 568 Proizvodstvo na akril
Page 587 and 588:
na izreagiran propilen (AK/P 0,82-
Page 589 and 590:
se dobivaat preku stehiometriskite
Page 591 and 592:
Granicite za re{avawe na ravenkite
Page 593 and 594:
Page 595 and 596:
578 T(V) Grafik 2. Promena na tempe
Page 597 and 598:
turata e T 520 K. Vo ovaa presmetk
Page 599 and 600:
smesa moè da se izrazi preku edins
Page 601 and 602:
inerti i amonijak. Koga vtoroto e s
Page 603 and 604:
586 k1 pC 2 R 0 K P ( atm ) ; (
Page 605 and 606:
duvanata reakcija. Ovaa operacija t
Page 607 and 608:
I dvata grafika, 2 i 3, pokaùvaat
Page 609 and 610:
( r A 592 F C F F F F To T T F
Page 611 and 612:
Sledniot ~ekor e da se sostavat mol
Page 613 and 614:
na i specifi~nata povr{ina na topli
Page 615 and 616:
[5] k1 = 1.79*(10^4)*exp(-20800/1.9
Page 617 and 618:
Stepen na konverzija na azot Stepen
Page 619 and 620:
602 1) UaV = 25000 kJ/(m 3 ·h·K)
Page 622 and 623:
LITERATURA 1. Levenspiel, Octave, C
Page 626:
ISBN 978-608-65044-3-4
show all

HEMISKI Zbirka re{eni zada~i REAKTORI 3

You also want an ePaper? Increase the reach of your titles

Delete template?

Save as template?