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Rock Mechanics.pdf - Mining and Blasting

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PRINCIPLES OF CLASSICAL STRESS ANALYSIS<br />

or<br />

2 ∂ ∂2<br />

+<br />

∂x 2 ∂y 2<br />

<br />

(xx + yy) = 0 (6.5)<br />

Equation 6.5 demonstrates that the two-dimensional stress distribution for isotropic<br />

elasticity is independent of the elastic properties of the medium, <strong>and</strong> that the stress<br />

distribution is the same for plane strain as for plane stress. The latter point validates<br />

the use of photoelastic plane-stress models in estimating the stress distribution in<br />

bodies subject to loading in plane strain. Also, as noted in section 6.1, equation 6.5<br />

demonstrates that the sum of the plane normal stresses, xx + yy, satisfies the Laplace<br />

equation.<br />

The problem is to solve equations 6.1 <strong>and</strong> 6.5, subject to the imposed boundary<br />

conditions. The method suggested by Airy introduces a new function U(x, y), in<br />

terms of which the stress components are defined by<br />

xx = ∂2 U<br />

∂y 2<br />

yy = ∂2 U<br />

∂x 2<br />

xy =− ∂2 U<br />

∂x ∂y<br />

(6.6)<br />

These expressions for the stress components satisfy the equilibrium equations 6.1,<br />

identically. Introducing them in equation 6.5 gives<br />

where<br />

∇ 4 U = 0<br />

∇ 2 = ∂2 ∂2<br />

+<br />

∂x 2 ∂y 2<br />

(6.7)<br />

Equation 6.7 is called the biharmonic equation.<br />

Several methods may be used to obtain solutions to particular problems in terms<br />

of an Airy stress function. Timoshenko <strong>and</strong> Goodier (1970) transform equations<br />

6.5 <strong>and</strong> 6.6 to cylindrical polar co-ordinates, <strong>and</strong> illustrate a solution procedure by<br />

reference to a thick-walled cylinder subject to internal <strong>and</strong> external pressure, as shown<br />

in Figure 6.2. For this axisymmetric problem, the biharmonic equation assumes the<br />

form<br />

d 4 U<br />

dr 4 + 2d3U 1<br />

−<br />

rdr 3 r 2<br />

for which a general solution for U is given by<br />

d2U 1<br />

+<br />

dr 2 r 3<br />

dU<br />

dr<br />

U = A ℓn r + Br 2 ℓn r + Cr 2 + D<br />

In this expression, the constants A, B, C, D are determined by considering both the<br />

169<br />

= 0

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