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Rock Mechanics.pdf - Mining and Blasting

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Figure 11.14 Example of a triangular<br />

roof prism.<br />

Figure 11.15 Design of a rockbolt<br />

or cable system to prevent sliding of<br />

a triangular prism (after Hoek <strong>and</strong><br />

Brown, 1980).<br />

SUPPORT AND REINFORCEMENT DESIGN<br />

equation 9.39 may be used. Substituting H0 = 20 MN (corresponding to a boundary<br />

stress of 5 MPa), 1 = 40 ◦ , 2 = 20 ◦ , 1 = 2 = 40 ◦ in equation 9.39 gives the vertical<br />

force required to produce limiting equilibrium of the prism as pℓ = 3.64 MN per<br />

metre thickness. Since the weight of the prism is W = 0.26 MN per metre thickness,<br />

it is concluded that the prism will remain stable under the influence of the induced<br />

elastic stresses.<br />

If the wedge is permitted to displace vertically so that joint relaxation occurs,<br />

the limiting vertical force is given by equation 9.40, with values of H being determined<br />

from equation 9.11. In the present case, the post-relaxation limiting vertical<br />

force is Pℓ = 0.18 MN per metre thickness. This is less than the value of W <strong>and</strong><br />

so, without reinforcement, the block will be unstable. The reinforcement force, R,<br />

required to maintain a given value of factor of safety against prism failure, F, is<br />

given by R = W − Pℓ/F. IfF = 1.5, then R = 0.14 MN per metre thickness. This<br />

force could be provided by grouted dowels made from steel rope or reinforcing<br />

bar.<br />

If the stabilising influence of the induced horizontal stresses were to be completely<br />

removed, it would be necessary to provide support for the total weight of the prism.<br />

For a factor of safety of 1.5, the required equivalent uniform roof support pressure<br />

would be 0.08 MPa, a value readily attainable using pattern rock bolting.<br />

Figure 11.15 shows a case in which a two-dimensional wedge is free to slide on<br />

a discontinuity AB. If stresses induced around the excavation periphery are ignored,<br />

tensioned rock bolt or cable support may be designed by considering limiting equilibrium<br />

for sliding on AB. If Coulomb’s shear strength law applies for AB, the factor<br />

of safety against sliding is<br />

F =<br />

cA+ (W cos + T cos ) tan <br />

W sin − T sin <br />

where W = weight of the block, A = area of the sliding surface, T = total force in<br />

the bolts or cables, = dip of the sliding surface, = angle between the plunge of<br />

the bolt or cable <strong>and</strong> the normal to the sliding surface, c, = cohesion <strong>and</strong> angle of<br />

friction on the sliding surface.<br />

Thus the total force required to maintain a given factor of safety is<br />

329<br />

T =<br />

W (F sin − cos tan ) − cA<br />

cos tan + F sin

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