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Rock Mechanics.pdf - Mining and Blasting

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ANSWERS TO PROBLEMS<br />

2 (a) 0.087 – 0.100 m; 0.083 – 0.104 m.<br />

(b) 26 m.<br />

3 48 ◦ .<br />

4 038/20.<br />

5 71 ◦ measured in the plane normal to the line of intersection.<br />

6 275/50.<br />

7 312/17.<br />

8 RMR = 69.<br />

Chapter 4<br />

1 Et = 14.3GPa, = 0.23.<br />

2 1 = 133.3MPa;1 = 85 MPa.<br />

3 (a) 1 = 133 + 3.03 MPa.<br />

3<br />

0.75<br />

4 1<br />

= 1.0 + 4.75 is one of several possible solutions.<br />

100 100<br />

5 s = 15.0 + n tan 27.5◦ MPa.<br />

7 (a) b = 30◦ , i = 15◦ .<br />

(b) Peak strength envelope bilinear with c = 0, = 45◦ for 0 < n < 1MPa,<br />

<strong>and</strong> c = 0.5 MPa, = 26.5◦ for 1 < n < 5 MPa. Residual strength<br />

envelope bilinear with cr = 0, r = 30◦ for 0 < n < 1MPa,<br />

<strong>and</strong> cr = 0.1 MPa,r = 26◦ for 1 < n < 5MPa.<br />

8 u = 1.247 MPa; u = 0.642 MPa.<br />

9 ′ 1 = 0.346 + 3.0′ 3 MPa.<br />

Chapter 5<br />

1 (b) i xx = 1.35 MPa, i zz = 1.35 MPa, i zx = 0.86 MPa.<br />

(c) xx = 3.51 MPa, zz = 4.59 MPa, zx = 0.86 MPa.<br />

1 = 5.07 MPa, 2 = 3.03 Mpa, 1 = 61.1 ◦<br />

2 pzz = 20.80 MPa, fissure water pressure u = 6.86 MPa.<br />

13.69 < pxx < 43.29 MPa.<br />

3 (a) Plane principal stresses are vertical <strong>and</strong> horizontal.<br />

(b) 1 = 20.0 MPa (vertical), 2 = 15.0 MPa (horizontal),<br />

3 = 12.0 MPa (parallel to tunnel axis).<br />

4 All stresses are in MPa.<br />

(b) pll = 10.22, pmm = 17.09, pnn = 10.68, plm =−1.30, pmn =−4.86,<br />

pnl = 1.12.<br />

(c) pxx = 15.59, pyy = 11.06, pzz = 11.35, pxy = 3.05, pyz = 3.12,<br />

pzx = 3.99.<br />

586

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