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Mathematical Methods for Physicists: A concise introduction - Site Map

Mathematical Methods for Physicists: A concise introduction - Site Map

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THE MATRIX EIGENVALUE PROBLEM<br />

is an eigenvector of A ~ corresponding to 1 ˆ 6. In the same way we ®nd the<br />

eigenvector corresponding to 2 ˆ 1:<br />

<br />

1<br />

X 2 ˆ :<br />

1<br />

Example 3.13<br />

If ~A is a non-singular matrix, show that the eigenvalues of ~A 1 are the reciprocals<br />

of those of ~A and every eigenvector of ~A is also an eigenvector of ~A 1 .<br />

Solution:<br />

that<br />

Let be an eigenvalue of ~A corresponding to the eigenvector X, so<br />

~AX ˆ X:<br />

Since ~A 1 exists, multiply the above equation from the left by ~A 1<br />

~A 1 ~AX ˆ ~A 1 X ) X ˆ ~A 1 X:<br />

Since ~A is non-singular, must be non-zero. Now dividing the above equation by<br />

, we have<br />

~A 1 X ˆ…1=†X:<br />

Since this is true <strong>for</strong> every value of ~A, the results follows.<br />

Example 3.14<br />

Show that all the eigenvalues of a unitary matrix have unit magnitude.<br />

Solution: Let ~U be a unitary matrix and X an eigenvector of ~U with the eigenvalue<br />

, so that<br />

~UX ˆ X:<br />

Taking the hermitian conjugate of both sides, we have<br />

X y ~U y ˆ *X y :<br />

Multiplying the ®rst equation from the left by the second equation, we obtain<br />

X y ~U y ~UX ˆ *X y X:<br />

Since ~U is unitary, ~U y ~U= ~I, so that the last equation reduces to<br />

X y X…jj 2 1† ˆ0:<br />

Now X y X is the square of the norm of X and hence cannot vanish unless X is a<br />

null vector and so we must have jj 2 ˆ 1orjj ˆ1; proving the desired result.<br />

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