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Mathematical Methods for Physicists: A concise introduction - Site Map

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BESSEL'S EQUATION<br />

Solution:<br />

Taking derivative of the quantity xJ 1 …x† with respect to x, we obtain<br />

d<br />

dx fxJ 1…x†g ˆ J 1 …x†‡xJ 0<br />

1…x†:<br />

Then using Eq. (7.92) with n ˆ 1, xJ 0<br />

1…x† ˆJ 1 …x†‡xJ 0 …x†, we ®nd<br />

thus,<br />

d<br />

dx fxJ 1…x†g ˆ J 1 …x†‡xJ 0<br />

1…x† ˆxJ 0 …x†;<br />

Z t<br />

0<br />

xJ 0 …x†dx ˆ xJ 1 …x†j t 0 ˆ tJ 1…t†:<br />

Approximations to the Bessel functions<br />

For very large or very small values of x we might be able to make some approximations<br />

to the Bessel functions of the ®rst kind J n …x†. By a rough argument, we<br />

can see that the Bessel functions behave something like a damped cosine function<br />

when the value of x is very large. To see this, let us go back to Bessel's equation<br />

(7.71)<br />

x 2 y 00 ‡ xy 0 ‡…x 2 2 †y ˆ 0<br />

and rewrite it as<br />

y 00 ‡ 1 x y 0 ‡<br />

1 2<br />

x 2 !<br />

y ˆ 0:<br />

If x is very large, let us drop the term 2 =x 2 and then the di€erential equation<br />

reduces to<br />

y 00 ‡ 1 x y 0 ‡ y ˆ 0:<br />

Let u ˆ yx 1=2 , then u 0 ˆ y 0 x 1=2 ‡ 1 2 x1=2 y, and u 00 ˆ y 00 x 1=2 ‡ x 1=2 y 0 1 4 x3=2 y.<br />

From u 00 we have<br />

Adding y on both sides, we obtain<br />

y 00 ‡ 1 x y 0 ˆ x 1=2 u 00 ‡ 1<br />

4x 2 y:<br />

y 00 ‡ 1 x y 0 ‡ y ˆ 0 ˆ x 1=2 u 00 ‡ 1<br />

4x 2 y ‡ y;<br />

x 1=2 u 00 ‡ 1<br />

4x 2 y ‡ y ˆ 0<br />

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