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Mathematical Methods for Physicists: A concise introduction - Site Map

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SPECIAL FUNCTIONS OF MATHEMATICAL PHYSICS<br />

By writing the series <strong>for</strong> the exponential and collecting powers of z, you can verify<br />

the ®rst few terms of the series. And it is also straight<strong>for</strong>ward to show that<br />

x @2 @<br />

‡…1 x†<br />

@x2 @x ‡ z @<br />

@z ˆ 0:<br />

Substituting the right hand side of Eq. (7.58), that is, …x; z† ˆP1<br />

nˆ0 ‰L n…x†=n!Šz n ,<br />

into the last equation we see that the functions L n …x† satisfy Laguerre's equation.<br />

Thus we identify …x; z† as the generating function <strong>for</strong> the Laguerre polynomials.<br />

Now multiplying Eq. (7.58) by z n1 and integrating around the origin, we<br />

obtain<br />

L n …x† ˆ n! I<br />

2i<br />

e<br />

xz=…1z†<br />

dz; …7:59†<br />

n‡1<br />

…1 z†z<br />

which is an integral representation of L n …x†.<br />

By di€erentiating the generating function in Eq. (7.58) with respect to x and z,<br />

we obtain the recurrence relations<br />

)<br />

L n‡1 …x† ˆ…2n ‡ 1 x†L n …x†n 2 L n1 …x†;<br />

…7:60†<br />

nL n1 …x† ˆnLn1…x†L 0 n…x†:<br />

0<br />

Rodrigues' <strong>for</strong>mula <strong>for</strong> the Laguerre polynomials L n …x†<br />

The Laguerre polynomials are also given by Rodrigues' <strong>for</strong>mula<br />

L n …x† ˆe x d n<br />

dx n …xn e x †:<br />

…7:61†<br />

To prove this <strong>for</strong>mula, let us go back to the integral representation of L n …x†, Eq.<br />

(7.59). With the trans<strong>for</strong>mation<br />

xz<br />

1 z ˆ s x or z ˆ s x ;<br />

s<br />

Eq. (7.59) becomes<br />

I<br />

L n …x† ˆn!ex<br />

2i<br />

s n e n<br />

…s x†<br />

n‡1<br />

ds;<br />

the new contour enclosing the point s ˆ x in the s plane. By Cauchy's integral<br />

<strong>for</strong>mula (<strong>for</strong> derivatives) this reduces to<br />

L n …x† ˆe x d n<br />

dx n …xn e x †;<br />

which is Rodrigues' <strong>for</strong>mula.<br />

Alternatively, we can di€erentiate Eq. (7.58) n times with respect to z and<br />

afterwards put z=0, and thus obtain<br />

e x @ n h<br />

<br />

lim<br />

z!0 @z n …1 z†1 exp x i<br />

ˆ L<br />

1 z n …x†:<br />

318

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