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Mathematical Methods for Physicists: A concise introduction - Site Map

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SERIES REPRESENTATIONS OF ANALYTIC FUNCTIONS<br />

Since r 1 = < 1, the last expression approaches zero as n !1. Hence<br />

lim n!1 R n2 ˆ 0 and we have<br />

f …z† ˆ 1 I<br />

" f …w†dw<br />

2i C 1<br />

w a ‡ 1 I #<br />

f …w†dw<br />

2i C 1 …w a† 2 …z a†<br />

"<br />

‡ 1 I #<br />

f …w†dw<br />

2i …w a† 3 …z a† 2 ‡<br />

C 1<br />

1<br />

‡ 1 I<br />

f …w†dw<br />

2i C 2<br />

<br />

z a ‡ 1 I<br />

…w a† f …w†dw<br />

2i C 2<br />

<br />

1<br />

…z a† 2 ‡:<br />

Since f …z† is analytic throughout the region between C 1 and C 2 , the paths of<br />

integration C 1 and C 2 can be replaced by any other curve C within this region<br />

and enclosing C 2 . And the resulting integrals are precisely the coecients a n given<br />

by Eq. (6.35). This proves the Laurent theorem.<br />

It should be noted that the coecients of the positive powers (z a) in the<br />

Laurent expansion, while identical in <strong>for</strong>m with the integrals of Eq. (6.28), cannot<br />

be replaced by the derivative expressions<br />

f n …a†<br />

n!<br />

as they were in the derivation of Taylor series, since f …z† is not analytic throughout<br />

the entire interior of C 2 (or C), and hence Cauchy's generalized integral<br />

<strong>for</strong>mula cannot be applied.<br />

In many instances the Laurent expansion of a function is not found through the<br />

use of the <strong>for</strong>mula (6.34), but rather by algebraic manipulations suggested by the<br />

nature of the function. In particular, in dealing with quotients of polynomials it is<br />

often advantageous to express them in terms of partial fractions and then expand<br />

the various denominators in series of the appropriate <strong>for</strong>m through the use of the<br />

binomial expansion, which we assume the reader is familiar with:<br />

…s ‡ t† n ˆ s n ‡ ns n1 t<br />

n…n 1†<br />

s n2 t 2 ‡<br />

2!<br />

n…n 1†…n 2†<br />

s n3 t 3 ‡:<br />

3!<br />

This expansion is valid <strong>for</strong> all values of n if jsj > jtj: If jsj jtj the expansion is<br />

valid only if n is a non-negative integer.<br />

That such procedures are correct follows from the fact that the Laurent expansion<br />

of a function over a given annular ring is unique. That is, if an expansion of the<br />

Laurent type is found by any process, it must be the Laurent expansion.<br />

Example 6.23<br />

Find the Laurent expansion of the function f …z† ˆ…7z 2†=‰…z ‡ 1†z…z 2†Š in<br />

the annulus 1 < jz ‡ 1j < 3.<br />

277

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