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Mathematical Methods for Physicists: A concise introduction - Site Map

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BESSEL'S EQUATION<br />

relation (7.77) breaks down when 2 ˆ k and a second solution has to be found<br />

by other methods. There is a diculty also when ˆ 0, in which case the two<br />

roots of the indicial equation are equal; the second solution must also found by<br />

other methods. These will be discussed in next section.<br />

The results of Problem 7.16 are a special case of an important general theorem<br />

which states that J …x† is expressible in ®nite terms by means of algebraic and<br />

trigonometrical functions of x whenever is half of an odd integer. Further<br />

examples are<br />

<br />

J 3=2 …x† ˆ 2 1=2 <br />

<br />

sin x<br />

cos x ;<br />

J 5=2 …x† ˆ 2<br />

x<br />

x x<br />

1=2 <br />

3 sin x<br />

x<br />

<br />

‡ 3 <br />

x 2 1 cos x<br />

The functions J …n‡1=2† …x† and J …n‡1=2† …x†, where n is a positive integer or zero, are<br />

called spherical Bessel functions; they have important applications in problems of<br />

wave motion in which spherical polar coordinates are appropriate.<br />

<br />

:<br />

Bessel functions of the second kind Y n …x†<br />

For integer ˆ n; J n …x† and J n …x† are linearly dependent and do not <strong>for</strong>m a<br />

fundamental system. We shall now obtain a second independent solution, starting<br />

with the case n ˆ 0. In this case Bessel's equation may be written<br />

xy 00 ‡ y 0 ‡ xy ˆ 0;<br />

…7:80†<br />

the indicial equation (7.73a) now, with ˆ 0, has the double root ˆ 0. Then we<br />

see from Eq. (7.33) that the desired solution must be of the <strong>for</strong>m<br />

y 2 …x† ˆJ 0 …x† ln x ‡ X1<br />

A m x m :<br />

Next we substitute y 2 and its derivatives<br />

mˆ1<br />

…7:81†<br />

y 0 2 ˆ J 0<br />

0 ln x ‡ J 0<br />

x ‡ X1<br />

mˆ1<br />

mA m x m1 ;<br />

y2 00 ˆ J0 00 ln x ‡ 2J 0<br />

0<br />

x J 0<br />

x 2 ‡ X1<br />

mˆ1<br />

m…m 1†A m x m2<br />

into Eq. (7.80). Then the logarithmic terms disappear because J 0 is a solution of<br />

Eq. (7.80), the other two terms containing J 0 cancel, and we ®nd<br />

2J 0<br />

0 ‡ X1<br />

mˆ1<br />

m…m 1†A m x m1 ‡ X1<br />

mˆ1<br />

mA m x m1 ‡ X1<br />

mˆ1<br />

A m x m‡1 ˆ 0:<br />

325

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