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Mathematical Methods for Physicists: A concise introduction - Site Map

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FOURIER SERIES AND INTEGRALS<br />

Using the integral<br />

Z 1<br />

0<br />

e 2 cos d ˆ 1 r<br />

<br />

e 2 =4 ;<br />

2 <br />

we ®nd<br />

T…x; t† ˆ 1 Z 1<br />

Z 1<br />

<br />

p<br />

2 f …u†e …ux†2 =4kt du f …u†e …u‡x†2 =4kt du :<br />

kt 0<br />

0<br />

p<br />

Letting …u x†=2<br />

<br />

p<br />

kt ˆ w in the ®rst integral and …u ‡ x†=2 kt ˆ w in the second<br />

integral, we obtain<br />

"<br />

T…x; t† ˆp<br />

1 Z 1<br />

p<br />

p<br />

<br />

f …2w Z 1<br />

kt ‡ x†dw ew2 p<br />

f …2w <br />

#<br />

p<br />

kt x†dw :<br />

ew2<br />

kt<br />

x=2<br />

x=2 <br />

kt<br />

Fourier trans<strong>for</strong>ms <strong>for</strong> functions of several variables<br />

We can extend the development of Fourier trans<strong>for</strong>ms to a function of several<br />

variables, such as f …x; y; z†. If we ®rst decompose the function into a Fourier<br />

integral with respect to x, we obtain<br />

f …x; y; z† ˆp<br />

1<br />

2<br />

Z 1<br />

1<br />

…! x ; y; z†e i! xx d! x ;<br />

where is the Fourier trans<strong>for</strong>m. Similarly, we can decompose the function with<br />

respect to y and z to obtain<br />

with<br />

f …x; y; z† ˆ 1 Z 1<br />

g…!<br />

…2† 2=3 x ;! y ;! z †e i…! xx‡! y y‡! z z† d! x d! y d! z ;<br />

1<br />

g…! x ;! y ;! z †ˆ 1 Z 1<br />

f …x; y; z†e i…! xx‡! y y‡! z z† dxdydz:<br />

…2† 2=3 1<br />

We can regard ! x ;! y ;! z as the components of a vector ! whose magnitude is<br />

q<br />

! ˆ ! 2 x ‡ ! 2 y ‡ ! 2 z;<br />

then we express the above results in terms of the vector !:<br />

f …r† ˆ 1 Z 1<br />

g…x†e ixr dx;<br />

…2† 2=3 1<br />

g…x† ˆ 1 Z 1<br />

f …r†e …ixr† dr:<br />

…2† 2=3 1<br />

…4:44†<br />

…4:45†<br />

182

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