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Mathematical Methods for Physicists: A concise introduction - Site Map

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FOURIER SERIES AND INTEGRALS<br />

amount of heat entering S per unit time is<br />

ZZ<br />

… KrT† ^ndS;<br />

S<br />

S<br />

where ^n is an outward unit vector normal to element surface area dS. Using the<br />

divergence theorem, this can be written as<br />

ZZ<br />

ZZZ<br />

… KrT† ^ndS ˆ r… KrT†dV: …4:38†<br />

Now the heat contained in V is given by<br />

ZZZ<br />

cTdV;<br />

V<br />

where c and are respectively the speci®c heat capacity and density of the solid.<br />

Then the time rate of increase of heat is<br />

ZZZ<br />

ZZZ<br />

@<br />

cTdV ˆ c @T<br />

@t<br />

@t dV:<br />

…4:39†<br />

V<br />

Equating the right hand sides of Eqs. (4.38) and (4.39) yields<br />

ZZZ <br />

c @T<br />

<br />

r KrT<br />

@t … † dV ˆ 0:<br />

V<br />

Since V is arbitrary, the integrand (assumed continuous) must be identically zero:<br />

or if K, c, are constants<br />

c @T<br />

@t<br />

V<br />

V<br />

ˆr … KrT †<br />

@T<br />

@t ˆ krrT ˆ kr2 T;<br />

…4:40†<br />

where k ˆ K=c. This is the required equation <strong>for</strong> heat conduction and was ®rst<br />

developed by Fourier in 1822. For the semiin®nite thin bar, the boundary conditions<br />

are<br />

T…x; 0† ˆf …x†; T…0; t† ˆ0; jT…x; t†j < M; …4:41†<br />

where the last condition means that the temperature must be bounded <strong>for</strong> physical<br />

reasons.<br />

A solution of Eq. (4.40) can be obtained by separation of variables, that is by<br />

letting<br />

Then<br />

T ˆ X…x†H…t†:<br />

XH 0 ˆ kX 00 H or X 00 =X ˆ H 0 =kH:<br />

180

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