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Mathematical Methods for Physicists: A concise introduction - Site Map

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COMPLEX INTEGRATION<br />

Figure 6.12.<br />

f 0 f …z<br />

…z 0 †ˆlim 0 ‡ h†f …z 0 †<br />

h!0 h<br />

I <br />

1<br />

ˆ lim<br />

h!0 2ih<br />

C<br />

1<br />

z …z 0 ‡ h† 1<br />

z z 0<br />

<br />

f …z†dz:<br />

Now<br />

<br />

1 1<br />

h z …z 0 ‡ h† 1 <br />

1<br />

ˆ<br />

z z 0 …z z 0 † 2 ‡ h<br />

…z z 0 h†…z z 0 † 2 :<br />

Thus,<br />

f 0 …z 0 †ˆ 1 I<br />

2i C<br />

f …z†<br />

…z z 0 † 2 dz ‡ 1<br />

2i lim h h!0<br />

IC<br />

f …z†<br />

…z z 0 h†…z z 0 † 2 dz:<br />

The proof follows if the limit on the right hand side approaches zero as h ! 0. To<br />

show this, let us draw a small circle of radius centered at z 0 (Fig. 6.12), then<br />

1<br />

2i lim<br />

h!0 h IC<br />

f …z†<br />

…z z 0 h†…z z 0 † 2 dz ˆ 1<br />

2i lim h h!0<br />

I<br />

f …z†<br />

…z z 0 h†…z z 0 † 2 dz:<br />

Now choose h so small (in absolute value) that z 0 ‡ h lies in and jhj =2 ˆ =2. Next, as f …z† is analytic in R, we can ®nd a positive<br />

number M such that j f …z†j M. And the length of is 2. Thus,<br />

I<br />

h<br />

2i<br />

<br />

f …z†dz<br />

…z z 0 h†…z z 0 † 2<br />

jj h M…2†<br />

2 …=2†… 2 † ˆ 2jhjM<br />

2 ! 0 as h ! 0;<br />

proving the <strong>for</strong>mula <strong>for</strong> f 0 …z 0 †.<br />

263

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