17.02.2014 Views

Mathematical Methods for Physicists: A concise introduction - Site Map

Mathematical Methods for Physicists: A concise introduction - Site Map

Mathematical Methods for Physicists: A concise introduction - Site Map

SHOW MORE
SHOW LESS

You also want an ePaper? Increase the reach of your titles

YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.

SPECIAL FUNCTIONS OF MATHEMATICAL PHYSICS<br />

or<br />

the solution of which is<br />

<br />

u 00 ‡ 1 <br />

<br />

4x 2 ‡ 1 x 1=2 y ˆ u 00 ‡ 1 <br />

4x 2 ‡ 1 u ˆ 0;<br />

u ˆ A cos x ‡ B sin x:<br />

Thus the approximate solution to Bessel's equation <strong>for</strong> very large values of x is<br />

y ˆ x 1=2 …A cos x ‡ B sin x† ˆCx 1=2 cos…x ‡ †:<br />

A more rigorous argument leads to the following asymptotic <strong>for</strong>mula<br />

<br />

J n …x† 2 1=2 <br />

cos x x<br />

4 n <br />

: …7:94†<br />

2<br />

For very small values of x (that is, near 0), by examining the solution itself and<br />

dropping all terms after the ®rst, we ®nd<br />

J n …x† <br />

x n<br />

2 n …n ‡ 1† : …7:95†<br />

Orthogonality of Bessel functions<br />

Bessel functions enjoy a property which is called orthogonality and is of general<br />

importance in mathematical physics. If and are two di€erent constants, we<br />

can show that under certain conditions<br />

Z 1<br />

0<br />

xJ n …x†J n …x†dx ˆ 0:<br />

Let us see what these conditions are. First, we can show that<br />

Z 1<br />

0<br />

xJ n …x†J n …x†dx ˆ J n…†J 0<br />

n…†J n …†J 0<br />

n…†<br />

2 2 : …7:96†<br />

To show this, let us go back to Bessel's equation (7.71) and change the independent<br />

variable to x, where is a constant, then the resulting equation is<br />

x 2 y 00 ‡ xy 0 ‡… 2 x 2 n 2 †y ˆ 0<br />

and its general solution is J n …x†. Now suppose we have two such equations, one<br />

<strong>for</strong> y 1 with constant , and one <strong>for</strong> y 2 with constant :<br />

x 2 y 00<br />

1 ‡ xy 0 1 ‡… 2 x 2 n 2 †y 1 ˆ 0; x 2 y 00<br />

2 ‡ xy 0 2 ‡… 2 x 2 n 2 †y 2 ˆ 0:<br />

Now multiplying the ®rst equation by y 2 , the second by y 1 and subtracting, we get<br />

x 2 ‰y 2 y 00<br />

1 y 1 y 00<br />

2 Š‡x‰y 2 y 0 1 y 1 y 0 2Šˆ… 2 2 †x 2 y 1 y 2 :<br />

336

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!