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Mathematical Methods for Physicists: A concise introduction - Site Map

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HERMITE'S EQUATION<br />

Rodrigues' <strong>for</strong>mula <strong>for</strong> Hermite polynomials H n …x†<br />

The Hermite polynomials are also given by the <strong>for</strong>mula<br />

H n …x† ˆ…1† n e x2<br />

dn<br />

dx n …ex2 †:<br />

To prove this <strong>for</strong>mula, let us write q ˆ e x2 . Then<br />

Dq ‡ 2xq ˆ 0;<br />

D ˆ d<br />

dx :<br />

Di€erentiate this (n ‡ 1) times by the Leibnitz' rule giving<br />

…7:42†<br />

Writing y ˆ…1† n D n q gives<br />

D n‡2 q ‡ 2xD n‡1 q ‡ 2…n ‡ 1†D n q ˆ 0:<br />

D 2 y ‡ 2xDy ‡ 2…n ‡ 1†y ˆ 0<br />

…7:43†<br />

substitute u ˆ e x2 y then<br />

Du ˆ e x2 f2xy ‡ Dyg<br />

and<br />

D 2 u ˆ e x2 fD 2 y ‡ 4xDy ‡ 4x 2 y ‡ 2yg:<br />

Hence by Eq. (7.43) we get<br />

D 2 u 2xDu ‡ 2nu ˆ 0;<br />

which indicates that<br />

u ˆ…1† n e x2 D n …e x2 †<br />

is a polynomial solution of Hermite's equation (7.38).<br />

Recurrence relations <strong>for</strong> Hermite polynomials<br />

Rodrigues' <strong>for</strong>mula gives on di€erentiation<br />

that is,<br />

H 0<br />

n…x† ˆ…1† n 2xe x2 D n …e x2 †‡…1† n e x2 D n‡1 …e x2 †:<br />

Eq. (7.44) gives on di€erentiation<br />

H 0<br />

n…x† ˆ2xH n …x†H n‡1 …x†:<br />

H 00<br />

n …x† ˆ2H n …x†‡2xH 0<br />

n…x†H 0<br />

n‡1…x†:<br />

…7:44†<br />

313

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