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Mathematical Methods for Physicists: A concise introduction - Site Map

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VECTOR DIFFERENTIATION OF A VECTOR FIELD<br />

The result is a vector ®eld. In the expansion of the determinant the operators<br />

@=@x i must precede V i ; P ijk stands <strong>for</strong> P P P<br />

i j k ; and " ijk are the permutation<br />

symbols: an even permutation of ijk will not change the value of the resulting<br />

permutation symbol, but an odd permutation gives an opposite sign. That is,<br />

" ijk ˆ " jki ˆ " kij ˆ" jik ˆ" kji ˆ" ikj ; and<br />

" ijk ˆ 0 if two or more indices are equal:<br />

A vector V is said to be irrotational if its curl is zero: rV…r† ˆ0. From this<br />

de®nition we see that the gradient of any scalar ®eld …r† is irrotational. The proof<br />

is simple:<br />

^e 1 ^e 2 ^e 3<br />

@ @ @<br />

r…r† ˆ<br />

@x 1 @x 2 @x 3<br />

…x 1 ; x 2 ; x 3 †ˆ0 …1:51†<br />

@ @ @<br />

@x 1 @x 2 @x 3<br />

<br />

because there are two identical rows in the determinant. Or, in terms of the<br />

permutation symbols, we can write r…r† as<br />

@ @<br />

r…r† ˆX<br />

" ijk^e i …x<br />

@x j @x 1 ; x 2 ; x 3 †:<br />

k<br />

ijk<br />

Now " ijk is antisymmetric in j, k, but @ 2 =@x j @x k is symmetric, hence each term in<br />

the sum is always cancelled by another term:<br />

@ @ @ @<br />

" ijk ‡ "<br />

@x j @x ikj ˆ 0;<br />

k @x k @x j<br />

and consequently r…r† ˆ0. Thus, <strong>for</strong> a conservative vector ®eld F, wehave<br />

curl F ˆ curl (grad † ˆ0.<br />

We learned above that a vector V is solenoidal (or divergence-free) if its divergence<br />

is zero. From this we see that the curl of any vector ®eld V(r) must be<br />

solenoidal:<br />

@<br />

r …r V† ˆX<br />

…r V†<br />

@x i ˆ X<br />

!<br />

@ X @<br />

"<br />

i @x ijk V<br />

i @x k ˆ 0; …1:52†<br />

j<br />

i<br />

because " ijk is antisymmetric in i, j.<br />

If …r† is a scalar ®eld and V(r) is a vector ®eld, then<br />

i<br />

j;k<br />

r…V† ˆ…r V†‡…r†V:<br />

…1:53†<br />

25

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