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Mathematical Methods for Physicists: A concise introduction - Site Map

Mathematical Methods for Physicists: A concise introduction - Site Map

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LINEAR VECTOR SPACES<br />

Linear combination<br />

A vector jWi is a linear combination of the vectors jv 1 i; jv 2 i; ...; jv r i if it can be<br />

expressed in the <strong>for</strong>m<br />

jWi ˆ k 1 jv 1 i‡k 2 jv 2 i‡‡k r jv r i;<br />

where k 1 ; k 2 ; ...; k r are scalars. For example, it is easy to show that the vector<br />

jWi ˆ…9; 2; 7† in E 3 is a linear combination of jv 1 i ˆ…1; 2; 1† and<br />

j i ˆ…6; 4; 2†. To see this, let us write<br />

v 2<br />

or<br />

…9; 2; 7† ˆk 1 …1; 2; 1†‡k 2 …6; 4; 2†<br />

…9; 2; 7† ˆ…k 1 ‡ 6k 2 ; 2k 1 ‡ 4k 2 ; k 1 ‡ 2k 2 †:<br />

Equating corresponding components gives<br />

k 1 ‡ 6k 2 ˆ 9; 2k 1 ‡ 4k 2 ˆ 2; k 1 ‡ 2k 2 ˆ 7:<br />

Solving this system yields k 1 ˆ3 and k 2 ˆ 2 so that<br />

jWi ˆ3jv 1 i‡ 2jv 2 i:<br />

Linear independence, bases, and dimensionality<br />

Consider a set of vectors j1i; j2i; ...; ji; r ... jiin n a linear vector space V. If every<br />

vector in V is expressible as a linear combination of j1i; ji; 2 ...; ji; r ...; jni, then<br />

we say that these vectors span the vector space V, and they are called the base<br />

vectors or basis of the vector space V. For example, the three unit vectors<br />

e 1 ˆ…1; 0; 0†; e 2 ˆ…0; 1; 0†, and e 3 ˆ…0; 0; 1† span E 3 because every vector in E 3<br />

is expressible as a linear combination of e 1 , e 2 , and e 3 . But the following three<br />

vectors in E 3 do not span E 3 : j1i ˆ…1; 1; 2†; j2i ˆ…1; 0; 1†, and j3i ˆ…2; 1; 3†.<br />

Base vectors are very useful in a variety of problems since it is often possible to<br />

study a vector space by ®rst studying the vectors in a base set, then extending the<br />

results to the rest of the vector space. There<strong>for</strong>e it is desirable to keep the spanning<br />

set as small as possible. Finding the spanning sets <strong>for</strong> a vector space depends upon<br />

the notion of linear independence.<br />

We say that a ®nite set of n vectors ji; 1 j2i; ...; ji; r ...; jni, none of which is a<br />

null vector, is linearly independent if no set of non-zero numbers a k exists such<br />

that<br />

X n<br />

kˆ1<br />

a k jki<br />

ˆj0i: …5:8†<br />

In other words, the set of vectors is linearly independent if it is impossible to<br />

construct the null vector from a linear combination of the vectors except when all<br />

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